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2 years ago

The monomial of the 2nd degree with a coeficcient of 3

Mathematics

2 answers:

shtirl [24]2 years ago

7 0

Answer:

Step-by-step explanation:

mono means one so there must only be one term, the number in front of the variable is the coefficient, n being squared makes it to the second degree

uranmaximum [27]2 years ago

4 0

I assume it is the last one, 3n^2, because the degree is the exponent, which is two and the three is the coefficient, which is next to the variable, plus it is a monomial, so there is only one term, eliminating the first two, the third one is just reversed. Therefore, the answer should be the last one. Hope this helps. :)

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Licemer1 [7]

Angles in a parallelogram have to equal 360.

Let x represent the measurement of the unknown angle.

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3 years ago

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vichka [17]

Answer:

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Step-by-step explanation:

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aev [14]

Answer:

$\frac{4(x - 5)(x + 7)(x - 12)}{(x + 1)(x)(x - 12)}$

Step-by-step explanation:

A rational function is

$\frac{p(x)}{q(x)}$

where q(x) doesn't equal zero.

If p is a asymptote, or hole at that value, then we will use

$(x - p)$

Step 1: We have asymptote as 0 and -1 so our denomiator will include

$(x - 0)(x - ( - 1)$

Which is

$(x)(x + 1)$

So our denomator so far is

$\frac{p(x)}{x(x + 1)}$

Step 2: Find Holes.

Since 12 is the value of the hole,

$(x - 12)$

is a the binomial.

This will be both on the numerator and denomator so qe have

$\frac{(x - 12)}{x(x + 1)(x - 12)}$

Step 3: Put the x intercepts in the numerator.

Since 5 and -7 is the intercepts,

$\frac{(x - 12)(x - 5)(x + 7)}{x(x + 1)(x - 12)}$

Step 4: Horinzontal Asymptotes,

Multiply the numerator and denomiator out fully,

$\frac{ {x}^{3} - 10 {x}^{2} - 59x + 420 }{ {x}^{3} - 12 {x}^{2} + x - 12}$

Take a L

look at the coefficients,

Notice they have the same degree,3, this means if we divide the leading coefficents, we will get our horinzonral asymptote.

Multiply the numerator by 4.

$\frac{4(x - 12)(x - 5)(x - 7)}{x(x + 1)(x - 12)}$

Above is the function,

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