PLEASE HELPPP ITS A TEST THAT IS DUE IN LIKE 20 MIN THIS IS THE LAST QUESTION.

Mathematics

2 answers:

expeople1 [14]2 years ago

5 0

Answer:

$35.16 Was the total amount spent at the restaurant.

Step-by-step explanation:

The first step is to change 20% to a decimal by moving the decimal point over twice.

20% → .20

Then, simply multiply .20 by 29.30.

.20 × 29.30 = 5.86

Okay, so- That was how to get the percentage for a number. Now, all you need to do is add 5.86 to the total bill to get the total amount spent. Like this:

29.30 + 5.86 = 35.16

Sergio039 [100]2 years ago

4 0

Answer:

$35.20

Step-by-step explanation: 29.30+20%=35.20

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The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

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a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that at least 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$