Zero × anything is zero, so no... you'll never see 0x. If for some reason you do, just rewrite the equation without it... because it's zero. :)
L*W*H
take them all and multipy
Answer:
(-9/7,-26/7)
[more detailed at the bottom of the explanation]
Step-by-step explanation:
I am assuming that this is a system of equations...
So, knowing that y is equal to x + 5, you would plug that in the second equation and find x. Then you would plug x and find y.
—————
Step 1)
Equation 1:
y = (x + 5)
Equation 2:
5x + 2y = 1
Equation 2 can also be written as:
5x + 2(x+5) = 1
I wrote x+5 instead of y because the first equation tells us that y is equal to x + 5.
—————
Step 2)
Solve for x .
5x + 2(x+5) = 1
5x + 2x + 10 = 1
7x + 10 = 1
7x = 1 - 10
7x = -9
x = -9/7
—————
Step 3)
Plug the x value back in the first equation.
y = -9/7 + 5
y = -26/7
—————
Solution:
x = -9/7
y = -26/7
In ordered pair form:
(-9/7,-26/7)
————— ————— —————
Hope this helps !!!!!!!
Answer:
y=3x-1
Step-by-step explanation:
If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,
navik [9.2K]
Answer:
{1,2,3,7}
Step-by-step explanation:
The range of a relation is the set of y-values of the ordered pairs.
The given relation is:
ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)},
The set of y-values of the given ordered pairs are;
{1,2,3,7}
Therefore the range of y is {1,2,3,7}
