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3 years ago

What is 2.3e-5 because I don't know what it is.

Mathematics

1 answer:

astraxan [27]3 years ago

3 0

0.000023 i hope that helps

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Henry just got a job at the mall. His job pays an hourly rate of $10.25.

nadezda [96]

Answer:

A. He will have to work 40 hours to buy the headphones

B. 1200 ≤ 10.25x ≤ 2000 where x is # of hrs worked

He can work anywhere between 118 and 196 hours.

Step-by-step explanation:

A. Divide 399.95 by 10.25 to get 39.01 hours. But since you cant work 0.01 of an hour, you have to round up to the next hour

B. You want to make more than or equal to 1200, so put that in the inequality. You want to make less or equal to 2000, so you put that in the inequality. In the middle, you put 10.25 an hour multiplied by the number of hours, which is a variable.

To solve, I made 10.25x = 1200, and x equaled 117.07, which rounds up to 118 hours because you cant work a 0.07 of an hour. 118 hours is the low number of the spectrum.

To solve for the highest number on the spectrum, you do 10.25x = 2000, and x equals 195.12, but since you cant work 0.12 of an hour, it rounds up to 196 hours.

3 0

1 year ago

What is the surface area

nexus9112 [7]

Answer:

A 1759 sq. units

Step-by-step explanation:

to find the surface area of a closed cylinder the formula is

2πr² + πdh

r = radius = 10

d = diameter = 10 + 10 = 20

2 x 3.14 x 10² + 3.14 x 20 x 18

628.3 + 1130.94 = 1759.24

ans = 1759

5 0

3 years ago

Solve for x to the nearest ten

swat32

Answer:

in right angled triangle ABC

by using Pythagoras law

h²=p²+b²

x²=7²+10²

x=√149=12.21cm

5 0

2 years ago

What is the volume of a figure with that is 2 inches wide, 7 inches tall and 9 inches<br> Pls help

Mnenie [13.5K]

Answer:

126

Step-by-step explanation:

What is the volume of a figure with that is 2 inches wide, 7 inches tall and 9 inchesn = Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

2x7x9 = 126

7 0

3 years ago

Read 2 more answers

Rationalise the denominator of:<br>1/(√3 + √5 - √2)

Paul [167]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} }$

can be re-arranged as

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} - \sqrt{2} + \sqrt{5} }$

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} }$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} } \times \dfrac{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }$

We know,

$\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}$

So, using this, we get

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ {( \sqrt{3} - \sqrt{2} )}^{2} - {( \sqrt{5}) }^{2} }$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{3 + 2 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{5 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{ - ( - \sqrt{3} + \sqrt{2} + \sqrt{5}) }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}}$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}} \times \dfrac{ \sqrt{6} }{ \sqrt{6} }$

$\rm \: = \: \dfrac{- \sqrt{18} + \sqrt{12} + \sqrt{30}}{2 \times 6}$

$\rm \: = \: \dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}$

$\rm \: = \: \dfrac{- 3\sqrt{2} + 2 \sqrt{3} + \sqrt{30}}{12}$

Hence,

$\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} } =\dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}}}$

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<h3><u>More Identities to </u><u>know:</u></h3>

$\purple{\boxed{\tt{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{3} = {x}^{3} + 3xy(x + y) + {y}^{3}}}}$

$\purple{\boxed{\tt{ {(x - y)}^{3} = {x}^{3} - 3xy(x - y) - {y}^{3}}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}}}$

6 0

3 years ago