Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
Note: √a * √a = a
√a * √b = √ab
(√2 + √10)² = (√2 + √10)(√2 + √10)
= √2(√2 + √10) + √10(√2 + √10)
= √2*√2 + √2*√10 + √10*√2 + √10*√10
= 2 + √20 + √20 + 10
= (2 + 10) + (√20 + √20)
= 12 + 2√20
√20 = √(4 *5) = √4 * √5 = 2√5
= 12 + 2√20 = 12 + 2(2√5)
= 12 + 4√5
Exponent form : 6^5
explanation :
we are given five 6's , so we simply start out with the number that is being multiplied over and over again .
which in this case , is 6.
6 • 6 • 6 • 6 • 6 = 7776
To make things easier though, we write repetitive numerals in exponent form. You will still get the same answer either way .
6^5 = 7776
answer : 6^5
Let
x---------> the length side of the rectangular area
y---------> the width side of the rectangular area
we know that
the area of the rectangle is equal to
-----> equation 
The perimeter of the rectangle is equal to
but remember that the fourth side of the rectangle will be formed by a portion of the barn wall
so
-----> equation 
<em>To minimize the cost we must minimize the perimeter</em>
Substitute the equation in the equation
![P=x+2*[\frac{200}{x} ]](https://tex.z-dn.net/?f=%20P%3Dx%2B2%2A%5B%5Cfrac%7B200%7D%7Bx%7D%20%20%5D%20)
Using a graph tool
see the attached figure
The minimum of the graph is the point 
that means for 
the perimeter is a minimum and equal to 
<u>Find the value of y</u>
The cost of fencing is equal to
therefore
<u>the answer is</u>
the length side of the the fourth wall will be 
