There goes principle albert

Meryl needs to add enough water to 11 gallons of an 18% detergent solution to make a 12% detergent solution. Which equation can

notka56 [123]

We're measuring a quantity of pure detergent.

We start with 11 gallons of an 18% solution. 18% of that, or 1.98 gallons, is pure detergent, and the rest of these 11 gal. is water: 9.02 gal. We will add x gallons of water to this solution to obtain (11+x) gallons of a 12% solution.

We need to find x to satisfy this equation:

(11 gallons + x)(0.12) = (11 gallons)(0.18)

Div. both sides by 0.12, we get (11 gallons + x) = (11 gallons)(1.5)

Mult. both sides by 10, we get 110 gallons + 10x = (11 gallons)(15)

Then 10x = 165 gallons - 110 gallons, or 55 gallons.

Div. both sides by 10, we get x = 5.5 gallons (answer)

6 0

3 years ago

What best describes a triangle with angles measuring 60 degrees 40 degrees and 100 degrees

sladkih [1.3K]

Obtuse triangle if that’s what you’re asking

8 0

3 years ago

Suppose a is directly proportional to b, but inversely proportional to c. If a=2 when b=5 and c=9, then what c is when b=3?

lakkis [162]

We will have 2 different equations that we will combine into 1, but we need to find the 2 k values first. If a is directly proportional to b, then a = kb. When a = 2 and b = 5, then k = 2/5. Store that for a minute. Now onto the second equation to find the other k value. If a is inversely proportional to c, then a=k/c. If a = 2 when c = 9, then k = 18. We will now use the transitive property: if a=kb and a = k/c, then kb=k/c. The k on the left is 2/5 and we are told that b = 3; the k on the right is 18 and we are looking for c. So here is what we have: $\frac{2}{5} (3)= \frac{18}{c}$ and $\frac{6}{5} = \frac{18}{c}$ . Cross multiply to get 6c = 90 and c = 15.

5 0

3 years ago

Read 2 more answers

Solve for x. 3x - 3 4x - 6 X = = [?]

Lina20 [59]

3x-3 and 4x-6 are complementary angles meaning together they add up to 180°. Set them equal to each other. So you get 3x-3=4x-6 now simplify this. Now you have x=3 and there you have it! If you plug 3 into x in both equations it works! Hope this helps!

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME!!!

VladimirAG [237]

Answer:

Part 1) $c=\sqrt{146}\ cm$

Part 2) $c=8\sqrt{2}\ in$

Part 3) The diagonal of rectangle is $d=3\sqrt{29}\ cm$

Part 4) The length of the diagonal of computer monitor is $d=15\ in$

Part 5) The ramp is $10.59\ ft$ long

Part 6) The distance between their houses is $=4\sqrt{2}\ mi$

Part 7) $234.31\ mi$

Part 8) 120 feet of wire is required

Step-by-step explanation:

Part 1) we know that

To find the length of the hypotenuse in a right triangle apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (the greater side)

a and b are the legs

we have

$a=11\ cm\\b=5\ cm$

substitute

$c^2=11^2+5^2$

$c^2=146$

$c=\sqrt{146}\ cm$

Part 2) we know that

To find the length of the hypotenuse in a right triangle apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (the greater side)

a and b are the legs

we have

$a=8\ in\\b=8\ in$

substitute

$c^2=8^2+8^2$

$c^2=128$

$c=\sqrt{128}\ in$

simplify

$c=8\sqrt{2}\ in$

Part 3) we know that

To find the length of the diagonal in a rectangle apply the Pythagorean Theorem

$d^2=b^2+h^2$

where

d is the diagonal of rectangle

b and h are the base and the height of rectangle

we have

$b=15\ cm\\hb=6\ cm$

substitute

$d^2=15^2+6^2$

$d^2=261$

$d=\sqrt{261}\ cm$

simplify

$d=3\sqrt{29}\ cm$

Part 4) we know that

To find the length of the diagonal of a computer monitor apply the Pythagorean Theorem

$d^2=w^2+h^2$

where

d is the diagonal of computer monitor

w and h are the wide and the high of computer monitor

we have

$w=12\ in\\h=9\ in$

substitute

$d^2=12^2+9^2$

$d^2=225$

$d=\sqrt{225}\ in$

simplify

$d=15\ in$

Part 5) we know that

To find out the length of the ramp apply the Pythagorean Theorem

$L^2=x^2+y^2$

where

L is the length of the ramp

x is the horizontal distance of the ramp

y is the vertical distance of the ramp

we have

$x=10\ ft\\y=3.5\ ft$

substitute

$L^2=10^2+3.5y^2$

$L^2=112.25$

$L=10.59\ ft$

Part 6) we know that

To find the distance between their houses apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (distance between their houses)

a and b are the legs

we have

$a=4\ mi\\b=4\ mi$

substitute

$c^2=4^2+4^2$

$c^2=32$

$c=4\sqrt{2}\ mi$

Part 7) we know that

The speed is equal to divide the distance by the time

$speed=distance/time$

so

the distance is equal to multiply the speed by the time

$distance=speed*time$

First train

speed=60 mph

time=3 hours

distance=60(3)=180 miles

Second train

speed=50 mph

time=3 hours

distance=50(3)=150 miles

To find out how far apart are the trains at the end of 3 hours apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (distance between the trains)

a and b are the legs

we have

$a=180\ mi\\b=150\ mi$

substitute

$c^2=180^2+150^2$

$c^2=54,900$

$c=234.31\ mi$

Part 8) we know that

For one tree is needed three wire

To find out the length of one wire apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (length of one wire)

a and b are the distance above the ground and the distance from the base

we have

$a=3\ ft\\b=4\ ft$

substitute

$c^2=3^2+4^2$

$c^2=25$

$c=5\ ft$

so

For one tree is required ----> (5)3=15 ft

therefore

For 8 trees is required

Multiply by 8

15(8)=120 ft

6 0

3 years ago