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2 years ago

HELPP !!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Umnica [9.8K]2 years ago

3 0

I cannot see the picture to good

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Need help i have been stuck on this problem

liberstina [14]

The second one is correct

4 0

3 years ago

Two-thirds of the T-shirts in a T-shirt shop are blue. Three-fifths of those T-shirts are on sale. One-half of the blue T

katrin2010 [14]

Let, total number of T-shirts are x.

Number of blue T-shirts = (2/3)x = 2x/3 .

Number of blue shirts on sale = (3/5)(2x/3) = 2x/5 .

Number of medium sized blue shirts on sale = (1/5)(2x/5) = 2x/25 .

Fraction of the shop's T-shirts are blue T-shirts that are on sale and are size medium = $\dfrac{2x/25}{x}$ = 2/25 . ( Number of medium sized blue shirts on sale divided by total number of T-shirts )

Hence, this is the required solution.

5 0

3 years ago

Please help me please please : ( : (

Gala2k [10]

Answer:

They will be picked up at 2 $\frac{1}{4}$ yards above sea level

Step-by-step explanation:

Let us consider sea level as reference and positions above sea level as positive and below sea level as negative.

With respect to this reference,

the position of top most point is +17 $\frac{3}{4}$ yards

and the position of lower most point is -13 $\frac{1}{4}$ yards

⇒ The position of midpoint is $\frac{+17 \frac{3}{4} - 13 \frac{1}{4}}{2}$

= +2 $\frac{1}{4}$

∴ <u>They will be picked up at 2 $\frac{1}{4}$ yards above sea level</u>

6 0

3 years ago

"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d

melisa1 [442]

First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]

5 0

3 years ago

PLEASE HELP ME !!!!!!!!

OLga [1]

Answer:

2nd option is correct...................................

4 0

1 year ago

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