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3 years ago

HELPP !!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Umnica [9.8K]3 years ago

3 0

I cannot see the picture to good

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Are there any numbers that go into 78 and 780

Kryger [21]

Are there any numbers that go into 78 and 780?

78 ÷ 2 = 39
780 ÷ 2 = 390

2 can be a number that goes in 78 and 780.

7 0

3 years ago

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100 Points!!! I will give Brainliest, a 5 star rating and a thank you. pls help me with question 1 through 5. 1 and 2 is on atta

julia-pushkina [17]

Answer:

1. A. similar

2. C.

3. B. all congruent figures are also similar figures.

4. B. 22.5

5. D. two hexagons

6 0

3 years ago

$500 shared in ratio 2:3:9

RideAnS [48]

2:3:9......added together = 14

2/14 (500) = 1000/14 = 71.43
3/14 (500) = 1500/14 = 107.14
9/14 (500) = 4500/14 = 321.43

6 0

3 years ago

Please help me I’m working on a math test and I’m struggling with this problem: The Aon center in Chicago is one of the worlds t

Nina [5.8K]

Answer:

They are 14.2 feet high each

Step-by-step explanation:

1136/80=14.2

4 0

2 years ago

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago