Diana had chocolate, and ate some, leaving 0.75 of it for Sarah.
Sarah ate 18.5 grams of it and return the rest to Diana, which was 65% of the original chococate.
how much chocolate did Diana have at the beginning?
and the solution is:
0.75x-18.50=0.65x
0.75x-0.65x=18.50
0.1x=18.50
x=185
so Diana had 185 grams of chocolate.
$10.8 rounding it to the nearest dollar is $10
Yes, 90 is 1/10 of 900
Because
90 = 1/10 x 900
90 = 90
Answer:
The expression could be used to verify g(x) is the inverse of f(x) is letter b which is 1/5(5x-25)+5
Step-by-step explanation:
Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
