All categories

3 years ago

Which of the following is another way to show the ratio 13 to 27?

Mathematics

1 answer:

Alisiya [41]3 years ago

7 0

Another ratio of 13:27 is to write it as a fraction. This is to mean;
$\frac{13}{27}$

You might be interested in

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago

Would like scatter plot image with line of best fit on the plot

dlinn [17]

Just take it in co-ordinate pairs

(x,y)=(Arm span,Height)

Take two points

(58,60)
(41,40)

Slope:-

$\\ \sf\longmapsto m=\dfrac{40-60}{41-58}$

$\\ \sf\longmapsto m=\dfrac{-20}{-17}$

$\\ \sf\longmapsto m=\dfrac{20}{17}$

$\\ \sf\longmapsto m\approx 1.2$

Equation of line in point slope form

$\\ \sf\longmapsto y-y_1=m(x-x_1)$

$\\ \sf\longmapsto y-60=1.2(x-58)$

$\\ \sf\longmapsto y-60=1.2x-69.6$

$\\ \sf\longmapsto 1.2x-y-9.6=0$

Convert to slope intercept form y=mx+b

$\\ \sf\longmapsto y=1.2x-9.6$

Graph attached

7 0

2 years ago

The complement of an angle is 25°. What is the measure of the angle?

Jlenok [28]

Answer:

If the complement of an angle is 25 degrees, then the measurement of the angle will be 65 degrees.

4 0

2 years ago

A cone has a volume of 226.08 cubic millimeters and a height of 6 millimeters. What is its

dezoksy [38]

Answer:

r≈5.36656314

Step-by-step explanation:

Since A=πr(r+ $\sqrt{h^2+r^2}$ ) so we get that 226.08/pi≈72 or 226.08/3.14=72 we then plug it in to get 72=r(r+ $\sqrt{36+r^2}$ ) so we get r≈5.36656314

6 0

3 years ago

Read 2 more answers

Geometry math question please help

Pie

Line BE and KE are the same length, so set the 2 equations to equal and solve for P.

7p+7 = 37-3p

Add 3 p to both sides:

10p +7 = 37

Subtract 7 from each side:

10p = 30

Divide both sides by 10:

p = 30/10

p = 3

The answer is B.

8 0

3 years ago

Read 2 more answers