Answer:
1/6z.
Step-by-step explanation:
25z^2 / 150z^3
25 divides 6 times into 150 and z^3 / z^2 = z
so the answer is 1/6z.
Answer:
<u>Shelter A</u>
Step-by-step explanation:
For Shelter A: the whiskers range from 8 to 30
so, the minimum weight of Shelter A is 8 pounds.
For For Shelter B: the whiskers range from 10 to 28
so, the minimum weight of Shelter B is 10 pounds.
<u> Which animal shelter has the dog that weighs the least? </u>
<u>The answer is: Shelter A</u>
Note: whiskers are plotted are from the minimum to Q1 and from Q2 to the max.
See the attached figure.
Answer:
A.6.2i-4.2 j
Step-by-step explanation:
We are given that
![u=9i-6j](https://tex.z-dn.net/?f=u%3D9i-6j)
![v=-3i-2j](https://tex.z-dn.net/?f=v%3D-3i-2j)
![w=19i+15j](https://tex.z-dn.net/?f=w%3D19i%2B15j)
We have to find the projection of w on to u.
The project of vector a on b
=![\frac{a\cdot b}{\mid b\mid^2}b](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5Ccdot%20b%7D%7B%5Cmid%20b%5Cmid%5E2%7Db)
![w.u=(19i+15j)\cdot (9i-6j)=171-90=81](https://tex.z-dn.net/?f=w.u%3D%2819i%2B15j%29%5Ccdot%20%289i-6j%29%3D171-90%3D81)
![\mid u\mid=\sqrt{x^2+y^2}=\sqrt{9^2+(-6)^2}=\sqrt{117}](https://tex.z-dn.net/?f=%5Cmid%20u%5Cmid%3D%5Csqrt%7Bx%5E2%2By%5E2%7D%3D%5Csqrt%7B9%5E2%2B%28-6%29%5E2%7D%3D%5Csqrt%7B117%7D)
Using the formula
The projection of w on to u
![=\frac{u\cdot w}{\mid u\mid^2}(u)=\frac{81}{117}(9i-6j)](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bu%5Ccdot%20w%7D%7B%5Cmid%20u%5Cmid%5E2%7D%28u%29%3D%5Cfrac%7B81%7D%7B117%7D%289i-6j%29)
The projection of w on to u=6.2i-4.2j
Hence, option A is true.
Answer:
Height : 3 cm
Step-by-step explanation:
The formula for a trapezoid is
<u> a+b</u> ×height
2
Rearrange for formula :
![2 \times \frac{area}{ base + base }](https://tex.z-dn.net/?f=2%20%5Ctimes%20%5Cfrac%7Barea%7D%7B%20base%20%2B%20base%20%7D%20)
![2\frac{9}{ 4 + 2 } = 3cm](https://tex.z-dn.net/?f=%202%5Cfrac%7B9%7D%7B%204%20%2B%202%20%7D%20%20%3D%203cm)