Find the 8th term of the geometric sequence whose common ratio is 3/2
and whose first term is 2.
1 answer:
Answer:
2187/64
Step-by-step explanation:
first term (a) = 2
common ratio (r) = 3/2
8th term (t8) = ?
We know
Tn = ar^ n - 1
t8 = 2 * (3/2)^ 8 - 1
= 2 * 2187/128
= 2187/64
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