2 years ago

Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 2.

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

7 0

Answer:

2187/64

Step-by-step explanation:

first term (a) = 2

common ratio (r) = 3/2

8th term (t8) = ?

We know

Tn = ar^ n - 1

t8 = 2 * (3/2)^ 8 - 1

= 2 * 2187/128

= 2187/64

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