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nikklg [1K]
3 years ago
11

Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 2.

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

2187/64

Step-by-step explanation:

first term (a) = 2

common ratio (r) = 3/2

8th term (t8) = ?

We know

Tn = ar^ n - 1

t8 = 2 * (3/2)^ 8 - 1

= 2 * 2187/128

= 2187/64

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Answer:

-(2×-4y)

Step-by-step explanation:

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3 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
lara [203]

Answer:

1. 12/13 and 5/13

2. 5/13 and 12/13

3. The sin of <A and cos of <B are congruent.

Since "Sine" is Opposite/Hypotenuse and Cosine is adjacent hypotenuse...

The opposite of angle A is 12, and the hypotenuse is 12, therefore making 12/13.

The adjacent of angle B is 12, (The adjacent side is the side next to the opposite that is not the hypotenuse) and the hypotenuse is 13, therefore making 12/13.   (The hypotenuse never changes no matter how you look at the triangle.)

Sin <A = 12/13

Cos <B= 12/13

7 0
3 years ago
In the table, the relation (x, y) is not a function if the missing value of x is___.
stepladder [879]
X is 6 that is the missing value in the equation

8 0
3 years ago
How is the formula for the circumference of a circle derived
Tanzania [10]

Answer:

Essentially by the definition of  

π

Step-by-step explanation:

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8 0
3 years ago
Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
Nonamiya [84]

Answer:

7

Step-by-step explanation:

Pythagorean Theorem:

25^2=24^2+x

625=576+x^2

49=x^2

x=sqrt49

x=7

Hope this helps!

Merry Christmas!

8 0
3 years ago
Read 2 more answers
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