2 years ago

Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 2.

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

7 0

Answer:

2187/64

Step-by-step explanation:

first term (a) = 2

common ratio (r) = 3/2

8th term (t8) = ?

We know

Tn = ar^ n - 1

t8 = 2 * (3/2)^ 8 - 1

= 2 * 2187/128

= 2187/64

You might be interested in

What is the y-coordinate of the point shown in the graph?

murzikaleks [220]

Answer:

3,-7

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

How can you divide 512 Dollars between two people So that one person can get $20 more than the other

Naya [18.7K]

Step-by-step explanation:

It is possible

One person will get 246 while the other will get 266 = 512

6 0

3 years ago

Read 2 more answers

Solve and explain how you did

Sliva [168]

Answer:

We conclude that:

$-\left(9x\right)^0=-1$

Step-by-step explanation:

Given:

$-\left(9x\right)^0$

To determine:

Explain how to solve the expression

<u>Solving the expression</u>

$-\left(9x\right)^0$

Apply the exponent rule

$a^0=1,\:\quad \:a\ne \:0$

so the expression becomes

$-\left(9x\right)^0\:=\:-1$

Therefore, we conclude that:

$-\left(9x\right)^0=-1$

4 0

3 years ago

A right triangle has a leg of 11 and a hypotenuse of 16. Find the missing leg (in simplest radical form)

wel

Answer: d

Step-by-step explanation:

6 0

3 years ago

Multiply and simplify.

Igoryamba

$(2x-1)(6x-7)=2x\cdot 6x-2x\cdot7-1\cdot 6x+1\cdot7=\\\\=12x^2-14x-6x+7=\boxed{12x^2-20x+7}$

Answer D.

4 0

3 years ago