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vazorg [7]
3 years ago
8

Two lengths of a triangle are shown

Mathematics
1 answer:
Luden [163]3 years ago
3 0
The length of BC would be 6ft
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Plz plz plz help on number 6,7,8,9 I would greatly appre and whoever gets it get brainliest
Luden [163]
6: Yes, it is linear. The constant rate of change is \frac{ y_{2}- y_{1} }{ x_{2}- x_{1} }, which you can make \frac{175-100}{10-5}. This simplifies to 15, so the constant rate of change is 15.

7. Yes, a proportional relationship exists because every output value is exactly three times every corresponding input value.

8. Yes, a proportional relationship exists because every output value is exactly \frac{3}{8} times the corresponding input value.

9. Yes, a proportional relationship exists because every y value is 7.5 times every corresponding x value, and if a line were to be drawn through the points, it would go through the origin (0,0).
7 0
3 years ago
What is the equation of the line that passes through the point (4,0) and has a slope<br> of -2
N76 [4]

Answer: y=-2x+8

Step-by-step explanation: Write a table of values where for every x y goes down 2 to find the y intercept (0,8) so it would be 8. The slope is -2 and that is all you need to write the equation.

8 0
10 months ago
A group of eight people are attending the movies together.
sveta [45]

Answer:

I think A

Step-by-step explanation:

4 0
3 years ago
Math the equation to the solution type​
Margarita [4]

Answer:

Step-by-step explanation:

1. 6x + 10 = 6x - 8

   10≠-8

no solution

2. 6x + 8 = 2x - 6

    4x + 8 = -6

     4x = -14

     x = -14/4= -7/2 one solution

3. 9x - 27 = 9x - 27

    0 = 0 All real no. infinitely many solution

6 0
2 years ago
I am stuck at this question​
Marrrta [24]

Answer:

Step-by-step explanation:

B(2,10); D(6,2)

Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)

Rhombus all sides are equal.

AB = BC = CD =AD

distance = √(x2-x1)² + (y2- y1)²

As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x

A(X,0)

AB = AD

√(2-x)² + (10-0)² = √(6-x)² + (2-0)²

√(2-x)² + (10)² =  √(6-x)² + (2)²

√x² -4x +4 + 100 =  √x²-12x+36 + 4

√x² -4x + 104 =  √x²-12x+40

square both sides,

x² -4x + 104 =  x²-12x+40

x² -4x - x²+ 12x = 40 - 104

             8x = -64

               x = -64/8

               x = -8

A(-8,0)

Let C(a,b)

M is AC midpoint

(-8+a/2, 0 + b/2)  = M(4,6)

     (-8+a/2, b/2)  = M(4,6)

Comparing;  

-8+a/2 = 4          ; b/2 = 6

  -8+a = 4*2       ; b = 6*2

  -8+a = 8          ; b = 12

        a = 8 +8

       a = 16

Hence, C(16,12)

6 0
3 years ago
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