(7r+3)(8r-2) = 7r(8r-2)+3(8r-2) = 56r^2-`14r + 24r-6
=56r^2+10r-6
Translating something horizontally is just like scooting a glass across a table. It doesn't flip or turn, it just slides. Same would apply for this. You just scoot the image over. Therefore, it would be 'C'
Answer:
it could hold 2772 square inches
Step-by-step explanation:
22x12x10.5=2772
I did this my sophmore year in highschool and I'm trying to remember lol. But first you add all the marbles together. 1+4+3. its eight. and since the marble was put back in this makes it an independant event. i believe the answer would be 2/8 considering that there isnt enough numbers to follow through with the equation of (P(a or b)=P(a)xP(b) . P is the probability and a and b are the variabls that represent the events. You would plug in the numbers of the probabilities into the equation, if you think the question calls for it. sorry it may not have been a staright up answer.
<h3>
<u>Answer:</u></h3>
<h3>
<u>Step-by-step explanation:</u></h3>
No , theres not enough information provided to Prove that both the triangles are congruent. Here in the figure we can see that there are two triangles ∆ BDA and ∆ BDC. And its given that
- AB = BC
- BD = BD ( common side )
The congruence conditions for two ∆s are :-
1) SAS ( Side Angle Side )
→ Two triangles are said to be congruent by SAS if two respective sides of the two triangles and the included angle between two sides are equal.
2) AAS ( Angle Angle Side )
→ Two triangles are said to be congruent by AAS if two angles and one side of triangle is congruent to other two angles and one side of the triangle .
3) SSS ( Side Side Side )
→ Two triangles are said to be congruent by SAS if all the three sides of one triangle is equal to three sides of the other triangle.
4) RHS ( Right Hypotenuse Side )
→ In two right-angled triangles, if the length of the hypotenuse and one side of one triangle, is equal to the length of the hypotenuse and corresponding side of the other triangle, then the two triangles are congruent.
And the given data doesn't satisfies any of the conditions.
<h3>
<u>Hence </u><u>there</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>enough</u><u> </u><u>information</u><u> provided</u><u> </u><u>to</u><u> </u><u>Prove </u><u>that </u><u>two</u><u> </u><u>triang</u><u>les</u><u> </u><u>are </u><u>cong</u><u>ruent</u><u> </u><u>.</u></h3>