X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
it says 8
Step-by-step explanation:
Answer:
z*113 -300
Step-by-step explanation:
(z*113) -300
7 2/3 + 8 5/6 = 16 1/2 ( or 32/2 )
Y = 30/20x + 20
( i haven’t done this in a while but i’m pretty sure this is right)
