What is the approximate radius of a sphere with a volume of 1436m^3
1 answer:
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Answer:
c = 0.165
Step-by-step explanation:
Given:
f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,
f(x, y) = 0 otherwise.
Required:
The value of c
To find the value of c, we make use of the property of a joint probability distribution function which states that
where a and b represent -infinity to +infinity (in other words, the bound of the distribution)
By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have
Since c is a constant, we can bring it out of the integral sign; to give us
Open the bracket
Integrate with respect to y
Substitute 0 and 3 for y
Add fraction
Rewrite;
The is a constant, so it can be removed from the integral sign to give
Integrate with respect to x
Substitute 0 and 3 for x
Multiply both sides by
Check the picture below. So, more or less looks like so.
notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.
Also notice, the "c" distance from the center to either foci, is just 5 units.
notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.
Also notice, the "c" distance from the center to either foci, is just 5 units.