Answer:
The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95
Step-by-step explanation:
Number of red marbles = 12
Number of green marbles = 8
Total number of marbles = 12+8 = 20
Probability of selecting red marble =![\frac{12}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B20%7D)
Since it is the case of no replacement
Remaining marbles = 20-1 = 19
Number of red marbles = 12-1=11
Number of green marbles = 8
Probability of selecting green marble =![\frac{8}{19}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B19%7D)
So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag =![\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B20%7D%20%5Ctimes%20%5Cfrac%7B8%7D%7B19%7D%3D%5Cfrac%7B24%7D%7B95%7D)
Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95