What is the current in a circuit if 3.50 C of charge passes any given point in a circuit in 1.80 s?
1 answer:
Answer:
I = 1.944 A
Explanation:
<u>Given the following data;</u>
Charge, Q = 3.5C
Time, t = 1.8 secs
Charge of a substance is given by the formula;
Where;
Q is the amount of charge measured in Colombs.
I is the current measured in Amperes.
t is the time measured in seconds.
Making I the subject of formula, we have
I = 1.944 A
Therefore, the current in the circuit is 1.944 Amperes.
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Answer:
(a)2.7 m/s
(b) 5.52 m/s
Explanation:
The total of the system would be conserved as no external force is acting on it.
Initial momentum = final momentum
⇒(4.30 g × 943 m/s) + (730 g × 0) = (4.30 g × 484 m/s) + (730 g × v)
⇒ 730 ×v = (4054.9 - 2081.2) =1973.7
⇒v=2.7 m/s
Thus, the resulting speed of the block is 2.7 m/s.
(b) since, the momentum is conserved, the speed of the bullet-block center of mass would be constant.
Thus, the speed of the bullet-block center of mass is 5.52 m/s.