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2 years ago

14

If a star collapses to a tenth its size, gravitation at its surface increases by?

1 answer:

tino4ka555 [31]2 years ago

8 0

If a star collapses to a tenth its size, gravitation at its surface increases by 100 times as much.

The contraction of an astronomical object caused by its own gravity, which tends to pull stuff inward toward the center of gravity, is known as gravitational collapse. A cloud of interstellar matter gradually collapses under the influence of gravity to form a star. The temperature rises as a result of the compression brought on by the collapse until thermonuclear fusion takes place in the star's core. At this point, the collapse gradually comes to an end as the outward heat pressure equalizes the gravitational forces. Following that, the star is in a condition of dynamic equilibrium. A star will repeatedly collapse once all of its energy sources have been used up until it reaches a new equilibrium condition.

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The potential energy between two atoms in a particular molecule has the form U(x) = 2.1 x 8 − 5.2 x4 where the units of x are le

a_sh-v [17]

Answer:

$x\approx 0.948$

Explanation:

The correct formula for the potential energy between two atoms in a particular molecule is:

$U(x) = \frac{2.1}{x^{8}}-\frac{5.2}{x^{4}}$

Where $x$ is the distance.

According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

$F = -\frac{dU}{dx}$

The function is derived in terms of distance:

$F (x) = \frac{84}{5\cdot x^{9}} -\frac{104}{5\cdot x^{5}}$

Then, it is needed to find at least of x so that F(x) equals to 0.

$\frac{84}{5\cdot x^{9}}-\frac{104}{5\cdot x^{5}}=0$

$\frac{84}{x^{4}}-104 = 0$

$84-104\cdot x^{4} = 0$

$x=\sqrt[4]{\frac{84}{104} }$

$x\approx 0.948$

7 0

3 years ago

A car goes around a curve at 20. m/s. If the radius of the curve is 40 m, what is the centripetal acceleration of the car?

Sergeeva-Olga [200]

Answer:

The centripetal acceleration of car is 8 m/s².

Explanation:

5 0

4 years ago

a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what

Andrews [41]

Answer:

v=9.6 km/s

Explanation:

Given that

The mass of the car = m

The mass of the truck = 4 m

The velocity of the truck ,u= 12 km/s

The final velocity when they stick = v

If there is no any external force on the system then the total linear momentum of the system will be conserve.

Pi = Pf

m x 0 + 4 m x 12 = (m + 4 m) x v

0 + 48 m = 5 m v

5 v = 48

$v=\dfrac{48}{5}\ km/s$

v=9.6 km/s

Therefore the final velocity will be 9.6 km/s.

3 0

3 years ago

How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?

Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

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3 years ago

A 5kg baby is asleep in a 5kg stroller. The mom is speed walking in the park at 3m/s. How much momentum does she generate with t

lesya [120]

Answer:

The correct solution is "15 kgm/s". A further explanation is given below.

Explanation:

The given values are:

Mass,

m = 5 kg

Velocity,

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⇒ $P=m v$

On substituting the given values, we get

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6 0

3 years ago