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2 years ago

If a star collapses to a tenth its size, gravitation at its surface increases by?

Physics

1 answer:

tino4ka555 [31]2 years ago

8 0

If a star collapses to a tenth its size, gravitation at its surface increases by 100 times as much.

The contraction of an astronomical object caused by its own gravity, which tends to pull stuff inward toward the center of gravity, is known as gravitational collapse. A cloud of interstellar matter gradually collapses under the influence of gravity to form a star. The temperature rises as a result of the compression brought on by the collapse until thermonuclear fusion takes place in the star's core. At this point, the collapse gradually comes to an end as the outward heat pressure equalizes the gravitational forces. Following that, the star is in a condition of dynamic equilibrium. A star will repeatedly collapse once all of its energy sources have been used up until it reaches a new equilibrium condition.

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A uniform meterstick of mass 0.20 kg is pivoted at the 40 cm mark. where should one hang a mass of 0.50 kg to balance the stick?

Tcecarenko [31]

The weight of the meterstick is:
$W=mg=0.20 kg \cdot 9.81 m/s^2 = 1.97 N$
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
$d_1 = 0.50 m - 0.40 m=0.10 m$
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
$M_w = W d_1 = (1.97 N)(0.10 m)=0.20 Nm$

To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
$(mg) d_2 = 0.20 Nm$
from which we find the value of d2:
$d_2 = \frac{0.20 Nm}{mg}= \frac{0.20 Nm}{(0.5 kg)(9.81 m/s^2)}=0.04 m$

So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.

4 0

4 years ago

As the distance between two objects increases, the gravitational force of attraction between them will

jeka94

That force DEcreases. This is a big part of the reason why the Earth attracts you with more force than Jupiter does.

4 0

3 years ago

A simple series circuit consists of a 150 Ω resistor, a 29 V battery, a switch, and a 2.1 pF parallel-plate capacitor (initially

Rufina [12.5K]

Find the electric flux and the disp at t=0.50ns
Given: 
Resistor R = 160 Ω 
Voltage ε = 22.0 V 
Capacitor C = 3.10 pF = 3.10 * 10^-12 F 
time t = 0.5 ns = 0.5 * 10^-9 s 
ε0 = 8.85 * 10^-12 
Solution: 
ELECTRIC FLUX: 
Φ = Q/ε0 
we have ε0, we need to find Q the charge 
STEP 1: FIND Q 
Q = C ε ( 1 - e^(-t/RC) ) 
Q = { 3.10 * 10^-12 } { 22.0 } { 1 - e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } 
Q = { 3.10 * 10^-12 } { 22.0 } { 1 - 0.365 } 
Q = { 3.10 * 10^-12 } { 22.0 } { 0.635 } 
Q = 43.31 * 10^-12 C 
STEP 2: WE HAVE Q AND ε0 > >>> SOLVE FOR ELECTRIC FLUX >>> 
Φ = Q/ε0 
Φ = { 43.31 * 10^-12 C } / { ε0 = 8.85 * 10^-12 } 
Φ = 4.8937 = 4.9 V.m 
DISPLACEMENT CURRENT 
we use the following equation: 
I = { ε / R } { e^(-t/RC) } 
I = { 22 / 160 } { e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } 
I = { 0.1375 } { 0.365 } 
I = 0.0502 A = 0.05 A

8 0

3 years ago

Compare and contrast the health benefits and the amount of physical or mental energy needed between active leisure activities an

dolphi86 [110]

This is the answer "Some active leisure activities, such as yoga and running, require a great deal of physical energy, while other activities, like playing chess, require a substantial amount of mental energy. Passive leisure activities, such as watching TV or going to the movies, require little to no physical or mental energy. Because of the exertion of physical or mental energy, active leisure activities have more health benefits than passive leisure activities." hope it help you?:)

4 0

3 years ago

(a) An object that has a small mass and an object that has a large mass have the same momentum. Which object has the largest kin

Iteru [2.4K]

Answer:

A) The smaller object; B) The larger object

Explanation:

A) Lets say the small object is 2 kg and the large one is 6 kg. Lets say they also have 30 kg*m/s of momentum each. The small object would have 15 m/s velocity and the large would have 5 m/s.

Now for kinetic energy(.5*m*v²), the small object is .5*2*15², which is 225 J

The large object is .5*6*5², which is 75 J, so the smaller object has more Kinetic energy. Since velocity is squared, it is more important than how large mass is.

B) Same masses as part A. Lets say the kinetic energy is 45 J for both of them. For the small object, 45=.5*2*v²

.5*2 is 1, so 45/1 is 45. Take the square root and we get v= 6.71 m/s

For the large object, 45=.5*6*v²

.5*6 is 3, so 45/3 is 15. Take the square root and we get v=3.87 m/s

Now we plug the velocities into p=mv

For the small object, p=2*6.71, which gives us p=13.42 kg*m/s

For the large object, p=6*3.87, which gives us p=23.22 kg*m/s

The larger object has the larger momentum.

Hope this helps

5 0

3 years ago