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Rudiy27
2 years ago
14

If a star collapses to a tenth its size, gravitation at its surface increases by?

Physics
1 answer:
tino4ka555 [31]2 years ago
8 0

If a star collapses to a tenth its size, gravitation at its surface increases by 100 times as much.

The contraction of an astronomical object caused by its own gravity, which tends to pull stuff inward toward the center of gravity, is known as gravitational collapse. A cloud of interstellar matter gradually collapses under the influence of gravity to form a star. The temperature rises as a result of the compression brought on by the collapse until thermonuclear fusion takes place in the star's core. At this point, the collapse gradually comes to an end as the outward heat pressure equalizes the gravitational forces. Following that, the star is in a condition of dynamic equilibrium. A star will repeatedly collapse once all of its energy sources have been used up until it reaches a new equilibrium condition.

To learn more about Star:

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PLEASE HELP WILL GIVE BRAINLIEST!!!!
zimovet [89]

Answer:

pelvic gridle

Explanation:

8 0
3 years ago
A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i
Veseljchak [2.6K]

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.

Explanation:

For an inelastic collision:

  • The total momentum of the system is conserved
  • The total kinetic energy of the system is not conserved

Using these facts, let's now analyze each statement given.

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.  --> TRUE. Since the total momentum is conserved, we can write:

p_1 = p_1'+p_2'

where

p_1 is the initial momentum of the 5-kg ball

p_1' is the final momentum of the 5-kg ball

p_2' is the final momentum of the 10-kg ball

The equation can be rewritten as

p_1-p_1'=p_2'

which is equivalent to

-\Delta p_1 = \Delta p_2

which means that the magnitude of the change of momentum of the two balls is the same.

b. Both balls lose all their momentum since the collision is inelastic.  --> FALSE, the 10-kg ball gains momentum, so it does not lose it.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.  --> TRUE. We already said that the magnitude of the change in momentum of the two balls is the same. However, it can be written as

\Delta p = m\Delta v

where m is the mass of the ball and \Delta v its change in velocity. Therefore, the 5-kg ball (which has smaller mass) will have a larger \Delta v, so a larger change in velocity.

d. The magnitude of the change of velocity the 5-kg ball experiences is equal to that of the 10-kg ball.  --> FALSE, as we discussed in c).

e. The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball. --> FALSE, as we discussed in c).

Learn more about change in momentum:

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6 0
3 years ago
if the current through a resistor is increased by a factor of 4, how does this affect the power dissipated?
lbvjy [14]

The new current will be 4I. The power dissipated by the resistor will increase by a factor of 16.

<h3>What is a resistor?</h3>
  • Using electrical resistance as a circuit element, a resistor is a passive electrical component with two terminals. In electrical circuits, resistors are used, among other things, to limit current flow, modify signal levels, divide voltages, bias active devices, and terminate transmission lines.
  • As test loads for generators, power distribution systems, and motor controls, high-power resistors that can create many watts of heat rather than just electrical energy can be used.
  • Variable resistors can be used as sensors for force, heat, light, humidity, humidity, and chemical activity or for adjusting circuit components.
  • Electrical networks and electronic circuits frequently contain resistors, which are found everywhere in electronic equipment. Practical resistors are discrete components that come in a wide range of materials and forms.

To learn more about resistor refer :

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4 0
1 year ago
Will Give Brainliest and 25 Points
Vikentia [17]

This is the Doppler effect.

1. As the sound leaves the horn the sound waves are at first close to each other and as they move outwards they become further apart. The closer the sound waves are the louder the noise.

As the car gets the closer the sound waves get closer, so the horn becomes louder.

2. As the horn moves away, the sound waves become less frequent, causing the pitch to get lower.

5 0
3 years ago
A total of 25.6 kJ of heat energy is added to a 5.46 L sample of helium at 0.991 atm. The gas is allowed to expand against a fix
bagirrra123 [75]

Answer:

(a) W = 1329.5 J = 1.33 KJ

(b) ΔU = 24.27 KJ

Explanation:

(a)

Work done by the gas can be found by the following formula:

W = P\Delta V

where,

W = Work = ?

P = constant pressure = (0.991 atm)(\frac{101325\ Pa}{1\ atm}) = 100413 Pa

ΔV = Change in Volume = 18.7 L - 5.46 L = (13.24 L)(\frac{0.001\ m^3}{1\ L}) = 0.01324 m³

Therefore,

W = (100413 Pa)(0.01324 m³)

<u>W = 1329.5 J = 1.33 KJ</u>

<u></u>

(b)

Using the first law of thermodynamics:

ΔU = ΔQ - W (negative W for the work done by the system)

where,

ΔU = change in internal energy of the gas = ?

ΔQ = heat added to the system = 25.6 KJ

Therefore,

ΔU = 25.6 KJ - 1.33 KJ

<u>ΔU = 24.27 KJ</u>

3 0
3 years ago
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