X-246-c4779952vhjjj23467890865
Answer:
2.81
Step-by-step explanation:
.81 has a bar over it.
Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
Answer:
4 and 13
Step-by-step explanation:
You want integer solutions to ...
15 ≤ n(n+1) ≤ 200
If we let the limits be represented by "a", then the equality is represented by ...
n² +n -a = 0
(n² +n +1/4) -a -1/4 = 0
(n +1/2)^2 = (a +1/4)
n = -1/2 + √(a +1/4)
For a=15, we have
n ≥ -1/2 + √15.25 ≈ 3.4 . . . . . minimum n is 4
For a=200, we have
n ≤ -1/2 + √200.25 ≈ 13.7 . . . maximum n is 13
The least and greatest integers on the cards are 4 and 13.