It’s C. An MP3 file is an audio/video file, so only a media player would be able to play this
Answer:
Option (d) is the correct answer.
Explanation:
An Array is used to store multiple variables in the memory in the continuous memory allocation on which starting index value is starting from 0 and the last index value location is size-1.
In java programming language the array.length is used to tells the size of the array so when the user wants to get the value of the last element, he needs to print the value of (array.length-1) location so the correct statement for the java programming language is to print the last element in the array named ar is--
System.out.println(ar[ar.length-1]);
No option provides the above statement, so option d (None of these) is correct while the reason behind the other option is not correct is as follows--
- Option a will prints the size of the array.
- Option b also gives the error because length is an undeclared variable.
- Option c will give the error of array bound of an exception because it begs the value of the size+1 element of the array.
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
