Answer:
- import java.util.Scanner;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- System.out.print("Please enter two characters: ");
- String inputStr = input.nextLine();
-
- if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
- System.out.println("Biology");
- }
- else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
- System.out.println("Computer Science");
- }
- else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
- {
- System.out.println("Information Technology and Systems");
- }
- else{
- System.out.println("Invalid major");
- }
-
- int num = Character.getNumericValue(inputStr.charAt(1));
-
- if(num >= 1 && num <= 4){
- switch (num){
- case 1:
- System.out.println("freshman");
- break;
- case 2:
- System.out.println("sophomore");
- break;
- case 3:
- System.out.println("junior");
- break;
- case 4:
- System.out.println("senior");
- break;
- }
-
- }
- else{
- System.out.println("Invalid year status");
- }
-
- }
-
- }
Explanation:
The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.
The part 2 is to validate the year status to make sure it only fall within the range of 1-4 (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.
Answer: True
Explanation: "Ignore All" button is the button that operates when the user wants to ignore the word that is flagged .Flagged words are those which chosen by user to be banned and don't want to use in future.
Ignore all button helps in the ignoring of the spelling check of the words that the user is sure about and the words that user don't want to be the part of their content.This banning is for the future use and current time as well.Thus, the statement is true.
i'm needing help with the same question but mine gave choices, could you help please? thanks
A.
private network
B.
NOS
C.
network media
D.
network protocol
E.
directory service
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
