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alukav5142 [94]
3 years ago
6

2. (07.02 LC) How many solutions does the equation - 3y + 3y + 4 = 4 have?

Mathematics
1 answer:
Luden [163]3 years ago
7 0

Answer:

infinite

Step-by-step explanation:

to simplify 4=4 meaning all solutions are true

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This one pleaseeeeeeeeee helpppp
stiks02 [169]
Answer: x = 9

Remember: cross-multiply (product of the means equals the product of the extremes) to solve this proportion. It forms a 'cross'-- hence its name.

   4        8        4 and 2 are the extremes
------ = ------      8 and x - 8 are the means
x - 8      2        

(4)(2) = 8(x - 8)               Simplify
8 = 8(x - 8)                     Distributive Property
8 = 8x - 64                    Add 64 to both sides
72 = 8x                          Divide by 8 for both sides
9 = x                              Answer!
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3 years ago
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Help please don't get it
GarryVolchara [31]

Surface Area is the area of each face added together. For this question lets find the area of one triangle first.

Area of a triangle is base*hight/2, so 6*7/2=21. That was the area of one triangle. We have 4 traingle so we multiply that by for. 21*4=84.

Now, lets find the area of the squre. area of square is side*side or side^2.

So we multiply 6*6=36. that is the area of the square.

To find the surface area, we must add Area of Triangles+Area of Square.

so, 84+36=120

So the surface area is 120

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3 years ago
Mr. Jones told his students they each need half of a piece of paper. Calvin cut his piece of paper horizontally, and Matthew cut
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Neither or them have a bigger half. Hope it helps!
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3 years ago
2/5 expressed as a decimal
ch4aika [34]
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5 0
3 years ago
An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr
Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.  

He must pay an inventory fee of 52 per car and $5 per truck.  

He paid $849 for inventory foes.  

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}

Here we got n > number of cars and trucks, which is practically impossible.  

Hence, for the given conditions, we won’t get a practical solution

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3 years ago
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