What is the length of PR?<br><br> Can somebody solve this please?

Janet scored 200 and 400 points in the first 2 rounds of a computer game.

7nadin3 [17]

Answer:

B. $(200+400)-250=p$

Step-by-step explanation:

Let p be number of points Michael needs to score in 2nd game to catch up.

We have been given that Janet scored 200 and 400 points in the first 2 rounds of a computer game. So the total points scored by Janet in two games will be: $(200+400)$ points.

We are also told that Michael had scored 250 points in the first round and he want to get the same total score as Janet.

So we can find the number of points Michael needs to score to catch up Janet by subtracting the number of points scored by Michael in 1st game from total number of points scored by Janet in two games. We can represent this information in an equation as:

$(200+400)-250=p$

Therefore, the equation $(200+400)-250=p$ will help Michael to find the number of points he need to catch up Janet and option B is the correct choice.

3 0

4 years ago

Read 2 more answers

Researchers obtained a sample of n = 10 children who attended daycare before starting school. The children are given a standardi

attashe74 [19]

Answer:

$t=\frac{55.5-50}{\frac{4.249}{\sqrt{10}}}=4.093$

$p_v =2*P(t_{9}>4.093)=0.00084$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

We can say that at 5% of significance the true mean is significantly different from 50.

Step-by-step explanation:

Data given and notation

53, 57, 61, 49, 52, 56, 58, 62, 51, 56

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X))^2}{n-1}}$

And we got:

$\bar X=55.5$ represent the sample mean

$s=4.249$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =50/tex] represent the value that we want to test [tex]\alpha=0.05$ represent the significance level for the hypothesis test (ASSUMED).

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is equal or not to 50 :

Null hypothesis: $\mu = 50$

Alternative hypothesis: $\mu \neq 50$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{55.5-50}{\frac{4.249}{\sqrt{10}}}=4.093$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=10-1=9$

Since is a two-sided tailed test the p value would given by:

$p_v =2*P(t_{9}>4.093)=0.00084$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

We can say that at 5% of significance the true mean is significantly different from 50.

6 0

4 years ago

WILL MARK BRAINLIEST

Dennis_Churaev [7]

Find the area of the circle

A of circle = πr²

radius = diameter/2 = 48/2 = 24

Area = (3.14)(24)²
Area = 1808.64 in²

Hope this helps :)

6 0

4 years ago

How do you solve (Arc)QPT if <QZT = 120

yuradex [85]

By definition, the arc length is given by:
arc = R * theta * ((2 * pi) / 360)
Where,
theta: angle in degrees
R: radio
We have then:
(Arc) QPT if <QZT = 120:
theta = 360-120 = 240 degrees
R = 13.5 units
Substituting values we have:
(Arc) QPT = R * theta * ((2 * pi) / 360)
(Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
(Arc) QPT = 56.55 units
Answer:
(Arc) QPT = 56.55 units

7 0

4 years ago

PLEASE HELP!!! Write an absolute value equation representing all numbers x whose distance from 0 is 10 units.

tangare [24]

X would be the absolute value of 10 or -10 since they both are 10 units from 0 so it can be x=l10l or x=l-10l, they both equal 10

5 0

4 years ago

What is the length of PR? Can somebody solve this please?