3 years ago

Answer this for me please

Mathematics

1 answer:

babymother [125]3 years ago

5 0

The answer is A is cross the x axis at (2.2) :)

You might be interested in

Add first 15 natural numbers and find the average? Solution with formula?

kicyunya [14]

Answer:

120

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Function Composition: Let the function <img src="https://tex.z-dn.net/?f=f%28x%29%3D%203%2B6x" id="TexFormula1" title="f(x)=

V125BC [204]

Answer:

Given

f(x) = 3 + 6x

Find the inverse of f(x):

x = 3 + 6f⁻¹(x)
6f⁻¹(x) = x - 3
f⁻¹(x) = (x - 3) / 6

f · f⁻¹( ∛5/6) =
f( f⁻¹( ∛5/6)) =
f((∛5/6 - 3)/6) =
3 + 6((∛5/6 - 3)/6) =
3 + ∛5/6 - 3 =
∛5/6

f · f⁻¹(x) =
f(f⁻¹(x)) =
f((x - 3)/6) =
3 + 6(x - 3)/6 =
3 + x - 3 =
x

4 0

3 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

oksian1 [2.3K]

Answer: 0.0548

Step-by-step explanation:

Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.

Let $\overline{X}$ represents the sample mean GPA for each student.

Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:

$P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z$