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3 years ago

Find the 37th term of 352,345,338

Mathematics

1 answer:

Mariulka [41]3 years ago

8 0

Answer:

$a_{37}=100$

Step-by-step explanation:

Given that,

A sequence 352,345,338.

First term = 352

Common difference = 345-352 = -7

We need to find the 37th term of the sequence.

The nth term of an AP is given by :

$a_n=a+(n-1)d\\\\a_{37}=352+36\times (-7)\\\\a_{37}=100$

So, the 37th term of the sequence is 100.

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How to find minimum and maximum of this equation.

Westkost [7]

Using it's vertex, the maximum value of the quadratic function is -3.19.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

$y = ax^2 + bx + c$

The vertex is given by:

$(x_v, y_v)$

In which:

$x_v = -\frac{b}{2a}$

$y_v = -\frac{b^2 - 4ac}{4a}$

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If a > 0, the vertex is a minimum point.

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More can be learned about the vertex of a quadratic function at brainly.com/question/24737967

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