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steposvetlana [31]

3 years ago

11

There is a hot market at school for used graduation gowns, in fact the price is growing exponentially! Last week I could have go

tten one for $25, but today, one week later, the price is $37.50. What would the price be if I decide to wait to buy my graduation gown at graduation, six weeks from now?

1 answer:

Daniel [21]3 years ago

4 0

Answer:

$100

Step-by-step explanation:

the equation to solve this is:

$y=12.5x+25$

$y=12.5x+25\\ =(12.5*6)+25\\ =75+25\\ =100$

(Assuming, of course, that this is a homework assignment and not you actually buying it cuz' in real life the numbers would be different from month to month)

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Answer:

7/6= 1 1/6

Step-by-step explanation:

6+1/6= 7/6= 1 1/6

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2-7x-3x=-8x-8<br><br><br> Explain<br><br><br> Thanks

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3 years ago

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QUESTION 16<br> What is the absolute value of -72?

11Alexandr11 [23.1K]

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3 years ago

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Add the following polynomials, then place the answer in the proper location on the grid.

aivan3 [116]

Answer:

$x^3 - 6x + 2$

Step-by-step explanation:

The given polynomials can be added together by adding like terms together as shown below:

=> Add together, the coefficient of all terms that have the power of 3.

$(2x^3) + (x^3) + (-3x^3)$

$2x^3 + x^3 - 3x^3$

$3x^3 - 3x^3$

$x^3$

=> $(-4x^2) + (6x^2) + (2x^2)$

$-4x^2 + 8x^2$

$4x^2$

=> $(6x) + (-8x) + (-4x)$

$6x - 8x - 4x$

$-6x$

=> $(-3) + (12) +(-7)$

$-3 + 12 - 7$

$2$

The answer = $x^3 - 6x + 2$

5 0

3 years ago

: A new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.

d1i1m1o1n [39]

Answer:

2 bears in 2020.

Step-by-step explanation:

We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.

We will use exponential decay formula to solve our given problem as:

$y=a\cdot (1-r)^x$ , where,

y = Final quantity,

a = Initial value,

r = Decay rate in decimal form,

x = Time

$20\%=\frac{20}{100}=0.20$

Upon substituting our given values in above formula, we will get:

$y=150(1-0.20)^x$

$y=150(0.80)^x$ , where x corresponds to year 2000.

To find the population in 2020, we will substitute $x=20$ in our equation as:

$y=150(0.80)^{20}$

$y=150(0.011529215046)$

$y=1.7293822569$

$y\approx 2$

Therefore, 2 bears are there predicted to be in 2020.

Since population is decreasing so population is best described as exponential decay.

8 0

3 years ago