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Anon25 [30]
3 years ago
14

Which rational number equals 0 point 6 with bar over 6? (5 points)

Mathematics
2 answers:
Paraphin [41]3 years ago
5 0
Why you doing this ur just getting points
pochemuha3 years ago
5 0
6 over 10 i think because 0.6 is basically 6 tenths
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A line parallel to $3x-7y = 65$ passes through the point $(7,4)$ and $(0,K)$. What is the value of K?
Zepler [3.9K]

Answer:

1

Step-by-step explanation:

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6 0
3 years ago
The following table represents the altitude of a hiker climbing in Mountain over a 60 minute hike. Calculate the average rate of
Serggg [28]

Answer:

The correct answer is B. The rate of change is about 3 feet per minute

I hope this helped!

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3 years ago
Emily has a box where she stores her toys, the box has a height of 24 inches, a length of 40 inches, and a width of 10 inches. W
emmainna [20.7K]

Answer:

2)

Step-by-step explanation:

Volume of box = length * width * height

                         = 40 * 10 * 24

                         = 9600 cubic inches

5 0
3 years ago
If x = a cosθ and y = b sinθ , find second derivative
Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

\dfrac{\mathrm d^2y}{\mathrm dx^2}

Compute the first derivative. By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}

We have

y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta

x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta

and so

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta

Now compute the second derivative. Notice that \frac{\mathrm dy}{\mathrm dx} is a function of \theta; so denote it by f(\theta). Then

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}

By the chain rule,

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}

We have

f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta

and so the second derivative is

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta

4 0
3 years ago
The cost of a floral bouquet after a discount is applied is represented by the function below, where x represents the number of
galina1969 [7]

The average rate of change over the interval (12,24) is 2.17

Explanation:

Given that the cost of a floral bouquet after a discount is given by the function f(x)=2.17x-10.00

We need to determine the average rate of change over the interval (12,24)

The average rate of change can be determined using the formula,

\frac{f(b)-f(a)}{b-a}

where a=12 and b=24

Substituting the value of a and b in the function, we get,

f(12)=2.17(12)-10.00

        =26.04-10.00

        =16.04

f(24)=2.17(24)-10.00

        =52.08-10.00

        =42.08

Hence, substituting these values in the formula, we get,

\frac{f(b)-f(a)}{b-a}=\frac{42.08-16.04}{24-12}

Simplifying, we get,

\frac{f(b)-f(a)}{b-a}=\frac{26.04}{12}

Dividing, we have,

\frac{f(b)-f(a)}{b-a}=2.17

Thus, the average rate of change over the interval (12,24) is 2.17

7 0
3 years ago
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