Why is (3, –5) not a solution to the system of equations given below?
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Hello!
The equation for a circle is
r is the radius
To find the radius we take the square root of the number in the radius spot
sqrt169 = 13
The answer is 13
Hope this helps!
The equation for a circle is
r is the radius
To find the radius we take the square root of the number in the radius spot
sqrt169 = 13
The answer is 13
Hope this helps!
As I've shown on picture that I attached:
∠ADC=∠ADB+∠BDC⇒134=5x+4+7x-2
12x+2=134
12x=132⇒x=132/12
x=11
Angle BDC measure 7x-2=7*11-2⇒∠BDC=75.
∠ADC=∠ADB+∠BDC⇒134=5x+4+7x-2
12x+2=134
12x=132⇒x=132/12
x=11
Angle BDC measure 7x-2=7*11-2⇒∠BDC=75.