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n200080 [17]
3 years ago
7

How do I solve this? Please show steps clearly so i can understand, thank you

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

The value of x=8.

Step-by-step explanation:

Given:

\frac{x+3}{x}-\frac{x+1}{x+4}=\frac{5}{x}

We need to solve this equation.

Solution:

First combining equation having same denominators we get;

\frac{x+3}{x}-\frac{5}{x}=\frac{x+1}{x+4}

Now denominators are common so we will solve the numerators we get;

\frac{x+3-5}{x}=\frac{x+1}{x+4}\\\\\frac{x-2}{x}=\frac{x+1}{x+4}

Now by cross multiplication we get;

(x-2)(x+4)=x(x+1)

Now Applying distributive property we get;

x^2+4x-2x-8=x^2+x\\\\x^2+2x-8=x^2+x

Now Combining the like terms we get;

x^2+2x-x^2-x=8\\\\x=8

Hence on solving we get the value of x=8.

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
When 27 times x squared times z all over negative 3 times x squared times z to the sixth power is completely simplified, the exp
marysya [2.9K]

Answer:

  -5 or 5 depending on how you write the simplified form

Step-by-step explanation:

\dfrac{27x^2z}{3x^2z^6}=9x^{2-2}z^{1-6}\\\\\boxed{=9z^{-5}=\dfrac{9}{z^5}}

__

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

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4 0
3 years ago
Find the distance between the points (5, -5) and (-7,4).
abruzzese [7]

Answer:

<h2>The answer is 15 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(5, -5) and (-7,4)

The distance between them is

d =  \sqrt{ ({5 + 7})^{2}  +  ({ - 5 - 4})^{2} }  \\  =  \sqrt{ {12}^{2}  + ( { - 9})^{2} }  \\  =  \sqrt{144 + 81}  \\  =  \sqrt{225}  \\  = 15 \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>15 units</h3>

Hope this helps you

4 0
3 years ago
Tia made a scale drawing of the White House for her history project. The actual length of the building is 168 feet, and its widt
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Answer:

c

Step-by-step explanation:

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An airplane travels about 1,500 Km in a straight line between Toronto and Winnipeg. However, the plane must climb to 10,000 m du
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Answer:416

Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:

The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km

and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km

So add the given results above with 500 km and this will be the additional distance that plane moves through the air.

The answer would be in the unit meters.

((10√401 +10√901−500)∗1000)=416 meters

Hope this is the answer that you are looking for.

7 0
3 years ago
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