Find the mean without the outlier <br>
15, 34, 38, 42, 43, 36, 40, 35, 36, 38,
Temka [501]
Is real confusing with this outliers
<span>When you write a number in expanded form you show how much each digit values, according its place in the number. For example, in the number 123, 3 values 3, 2 values 2*10 = 20 and 1 values 1*100 = 100, so the expanded form is 100 + 20 + 3. Using this with 84,000, you have the 8 is in the place of ten thousands, 4 is in the place of one thousand, 0 is in the place of hundreeds, 0 is in the place of tens, and 0 is in the place of units. So, the expanded form is: 80,000 + 4000. </span>
Answer:
a) Domain = 
b) ![x \in [0,100]](https://tex.z-dn.net/?f=x%20%5Cin%20%5B0%2C100%5D)
c) 53.03 worker hours
d) 83.33 worker hours
e) 83.33 worker hours
Step-by-step explanation:
We are given the following in the question:

where W(x) is the number of worker-hours required to distribute new telephone books to x% of the households in a certain rural community.
a) Domain of function.
The domain is the all the possible values of x that the function can take.
Domain = 
b) Values of x
Since x is a percentage in reference to context, it can only take value upto 100. Also it cannot take any negative value.
So domain n reference to context will be
![x \in [0,100]](https://tex.z-dn.net/?f=x%20%5Cin%20%5B0%2C100%5D)
c) worker-hours were required to distribute new telephone books to the first 70% of the households

53.03 worker hours were required to distribute new telephone books to the first 70% of the households.
d) Worker hour for entire community
For entire community, x = 100

83.33 worker hours were required to distribute new telephone books to the entire households.
e) Percentage of the households in the community for 3 worker hours

Thus, 4.74% of the households in the community had received new telephone books by the time 3 worker-hours had been expended.
To have a remainder 3, we take away 3 from each number first.
<u>Take away 3:</u>
224 - 3 = 221
250 - 3 = 247
302 - 3 = 299
<u>Prime factorisation of each of the numbers:</u>
221 = <span>13 x 17
247 = 13 x 19
299 = 13 x 23
<u>Find HCF:</u>
HCF = 13
Answer: The largest number that can be divided is 13.</span>