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3 years ago

Please help me with #13 and #14! Please explain how you did it! Thanks!

Mathematics

2 answers:

natulia [17]3 years ago

7 0

#13 is the first one and #14 is the last, if need to explain, reply back plz

denis-greek [22]3 years ago

3 0

13) 2x + 5 = 2x + 11 ⇒ the 2x cancels out on both sides leaving 5 = 11 which is a false statement so there is no solution that will make it a true statement.

14) -11k + 14 = -11k - 25 ⇒ same as above. the -11k cancels out leaving 14 = -25

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$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

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$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

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Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

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