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Marrrta [24]
3 years ago
9

Please help marking brainliest

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

A. The value of x is 5

B. The length of each side is 20!

Step-by-step explanation:

For part A., We can determine x by setting these equations to equal each other (as we know that all sides of a square are equal)! See below for how to:

4x = 2x +10\\2x = 10\\x=5

For part B. sub x for 5 to get the side length of one side...

4(5) = 20\\2(5) +10=20

We already know that all sides are equal, so the side length of each side is 20!

<em>Hope I was of assistance!</em> <em><u>#SpreadTheLove <3</u></em>

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Answer:

∠a and ∠d; ∠b and ∠c

Step-by-step explanation:

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The sides measuring 6 and 3 are corresponding sides

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Step-by-step explanation:

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3 years ago
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A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

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                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

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