A farmer has 300 ft of fencing with which to enclose a rectangular pen next to a barn. The barn itself will be used as one of th
e sides of the enclosed area.
What is the maximum area that can be enclosed by the fencing?
Enter your answer in the box.
ft²
What is the maximum area that can be enclosed by the fencing?
Enter your answer in the box.
ft²
1 answer:
Let x represent the length of the side of the pen that is parallel to the barn. Then the area (y) will be
.. y = x(300 -x)/2
This describes a downward opening parabola with zeros at x=0 and x=300. The vertex (maximum) will be found at the value of x that is halfway between those, x = 150.
For that value of x, the pen area is
.. y = 150(300 -150)/2 = 150^2/2 = 11,250 . . . . . square feet.
.. y = x(300 -x)/2
This describes a downward opening parabola with zeros at x=0 and x=300. The vertex (maximum) will be found at the value of x that is halfway between those, x = 150.
For that value of x, the pen area is
.. y = 150(300 -150)/2 = 150^2/2 = 11,250 . . . . . square feet.
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Answer:
0.5 m
Step-by-step explanation:
Given that the dimensions of the garden are 15 meters by 20 meters.
The area of the new garden (original garden + stone placed around the perimeter) is 336m².
Let d be the width of the border having stepping stones as shown in the figure. The shaded region in the figure is the area having stepping stones.
The area including the shaded region
As the width of the stone border can't be a negative value, so taking the positive value.
Hence, the width of the stone border is 0.5 m.
So, the wi