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3 years ago

If you ask the first 50 females who enter a restaurant to complete a survey about their experience, who is the sample?

Mathematics

2 answers:

balandron [24]3 years ago

8 0

Answer:

the first girl is the answer

Anettt [7]3 years ago

6 0

Answer:

the first girl

Step-by-step explanation:

because the first girl to take the survey is a sample but the rest that follows are just extras(can i get brainliest pls)

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Write the decimal as a fraction or a mixed number in simplest form. 4.02

Dima020 [189]

It's fraction form, 4.02 = 402/100 = 201/50

In mixed form, 4 1/50

8 0

3 years ago

The selling price of a refrigerator, is $739.20. If the mark up is 20% of the dealers cost , what is the dealers cost of the ref

Lisa [10]

Mark up percentages are used to increase the prices of items

The dealers cost of the refrigerator is $591.36

<h3>How to determine the dealer cost</h3>

Represent the dealer cost of the refrigerator with x.

Given that the markup is 20% and the selling price of the refrigerator is $739.20, then we have the following equation

x = 739.20 * (1 - 20%)

Evaluate the product

x = 591.36

Hence, the dealers cost of the refrigerator is $591.36

Read more about mark ups at:

brainly.com/question/19104371

5 0

2 years ago

7. Find the slope of the line through ( -2,6 ) & (3,14).

hammer [34]

14-6 over 3--2
8/5

.................,

5 0

3 years ago

Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3

Anastaziya [24]

Answer:

See explanation

Step-by-step explanation:

Given:

$A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]$

$B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]$

A. Find AB:

$AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]$

B. Find BA:

$BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]$