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Nataliya [291]
3 years ago
6

What is 28% of 14,350

Mathematics
2 answers:
Sonbull [250]3 years ago
7 0
Simply use a calculator:
(14350)*(.28)=4,018
xenn [34]3 years ago
5 0
Percent means parts out of 100 so
28%=28/100 or 0.28
'of' can be translated as multiply
28/100 times 14,350=401800/100=4018 or
0.28 times 14,350=4018
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\sf \dashrightarrow \:  -  \frac{2}{5}  - ( -  \frac{3}{10} ) - ( -  \frac{4}{7} )

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to +

\sf \dashrightarrow \:  -  \frac{2}{5}    + \frac{3}{10}  +  \frac{4}{7}

Calculate the LCM of denominators

\sf\frac{ - 28 + 21 + 40}{70}

Calculate the difference

\bf \underline{ \underline \frac{33}{70} }

7 0
2 years ago
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Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
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6 0
3 years ago
Who can help me ? please​
Masja [62]

Answer:

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Step-by-step explanation:

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4 0
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She spent 18 liters of jam!
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