Answer:
Step-by-step explanation:
It is given that the length of triangle base is 26, then let ABC be the triangle and BC be the base of the triangle=26.Let DE be the parallel line to the base that divides triangle ABC into two equal area parts.
Now, Let AD=a, DB=b, DE=c, AE=d and EC=e, then
Since, triangle ABC is similar to triangle ADE, thus using basic proportions, we get
Taking the first two equalities,we get
Thus, the length of the segment between triangle legs is 
8x + 6y = 10 ----------- (1)
5x - 3y = 2.2 ---------- (2)
(2) x 2:
10 x - 6y = 4.4 --------(2a)
(2a) + (1)
18x = 14.4
x = 1.8 ------- sub into (1)
8 (1.8) + 6y = 10
14.4 + 6y = 10
6y = 10 - 14.4
6y = - 4.4
y = - 0.73
There is 1 set of solution to it. (Answer C)
Answer: ten-thousandth's place
I probably spelled it wrong sorry lol. Spelling isn't my thing :)
Hope I helped!
Answer:
intersection is what point satisfies both equaitons
divide second equation by 2 for simplificy
2x-y=8
oh dear, we got the same equation
therefor they are the same line
infinitely many points
anywhere on the line 2x-y=8
some points are
(4,0)
(5,2)
