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3 years ago

Yes. im faling which means i need help asap

Mathematics

1 answer:

maxonik [38]3 years ago

5 0

20.5 is the correct answer

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62% of trees were saved from a fire. If this represents 1420 trees, how many trees were originally in the forest?Round to the ne

tresset_1 [31]

Answer:

2290 trees

Step-by-step explanation:

Given data

Let the total number of trees be x

62% of the total trees x is 1420 trees

mathematically

62/100x= 1420

0.62x= 1420

divide both sides by 0.62

x= 1420/0.62

x= 2290.32

To the nearest whole tree= 2290 trees

5 0

3 years ago

Find the length of the missing side. The triangle is not drawn to scale.

suter [353]

Answer:

D.) 8

Step-by-step explanation:

You can use the Pythagorean theorem because this is a right triangle:

$a^2+b^2=c^2$

a and b are the legs and c is the hypotenuse. The hypotenuse is always the longest side in a right triangle (since it is opposite the biggest angle). The two legs squared have to add up to the hypotenuse squared.

Fill in values:

$a^2+15^2=17^2$

Simplify exponents:

$a^2+225=289$

Isolate the variable. Subtract 225 from both sides:

$a^2+225-225=289-225\\a^2=64$

Find the square root of both sides:

$\sqrt{a^2}=\sqrt{64}\\ a=8$

The missing leg length is 8.

7 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .