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Gwar [14]
3 years ago
9

Write the decimal .0006 as a fraction

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

6/1000

Step-by-step explanation:

.0006 times 10,000

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−8/9⋅5/6 pls only correct answers. will give 30 points
Ivan

Answer:

- 20/27

Step-by-step explanation:

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3.467 rounded to the nearest tenth of an ounce
kicyunya [14]

The 4 is in the tenth place...so you have to look at the number beside it to see if you round up or down. It's a 6, which is greater than 5 so you round up.

3.5

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3 years ago
To prepare for a presentation, pete colored 1/2 of the poster and rebecca colored 1/3 of the poster, what fraction still needs t
WARRIOR [948]
Pete= 1/2

rebbeca= 2/3
6 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Can someone explain how to convert a quadratic function in standard form to vertex form using the "complete the square" method?
Arisa [49]

The required steps are explained below to convert the quadratic function into a perfect square.

<h3>What is the parabola?</h3>

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

Let the quadratic function be y = ax² + bx + c.

The first step is to take common the coefficient of x². We have

\rm y = a \left (x^2 + \dfrac{b}{a}x \right) + c

Add and subtract the half of the square the coefficient of x,

\rm y = a \left (x^2 + \dfrac{b}{a}x + \dfrac{b^2}{4a^2} \right) - a \times \dfrac{b^2}{4a^2} + c

Then we have

\rm y = a \left (x + \dfrac{b}{a} \right)^2 - \dfrac{b^2}{4a} + c

These are the required step to get the perfect square of the quadratic function.

More about the parabola link is given below.

brainly.com/question/8495504

#SPJ1

3 0
2 years ago
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