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Bumek [7]
3 years ago
13

Carl solved 20 math problems in 55 minutes how many math problems will carl solve in 75mins

Mathematics
2 answers:
Furkat [3]3 years ago
7 0
206.25
.....................
-BARSIC- [3]3 years ago
5 0
You need to find out how many problems Carl can do in a minute (unit rate), which is 20/55 or .36363636363. If you multiply it by 75 mins, you get 27.27, so the answer would be 27. 
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A clothing store charges $30 for 12 pairs of socks. A student says that the unit price is $0.40 per pair. What is the error? Wha
yulyashka [42]
Their error is that they divided 12 by 30, instead of 30 by 12 in order to get the price per pair

the correct unit price is $2.50 per pair

2.5 * 12 = 30
8 0
3 years ago
Read 2 more answers
PLLLSSSSS ANSWER THIS 40 POINTS
igomit [66]
0.03125 beciase there are 32 people and one ticket make that as a fraction which is 1/32 and make it a decimal
7 0
3 years ago
In order to ensure efficient usage of a server, it is necessary to estimate the mean number
juin [17]

Answer:

a. [36.19;39.21]

b. Reject the null hypothesis. The population mean of users that are connected at the same time is greater than 35.

Step-by-step explanation:

Hello!

Your study variable is,

X: "number of users of one server at a time"

The objective is to estimate the mean, for this, a sample of n=100 times was taken and the standard deviation S= 9.2 and the sample mean is X[bar]= 37.7 were calculated.

You need to study the population mean, for this you need your variable to have at least normal distribution. Since you don't have information about its distribution, but the sample is big enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample mean X[bar] to normal:

X[bar]≈N(μ;σ²/n)

a. With this approximation, you can construct the 90% Confidence Interval using the approximate Z

[X[bar] ± Z_{1-\alpha /2} * S/√n]

Z_{1-\alpha /2} = Z_{0.95} = 1.64

[37.7± 1.64* 9.2/√100]

[36.19;39.21]

b. You need to test if the population mean is greater than 35 with a level of significance of 1%.

The hypothesis is:

H₀: μ ≤ 35

H₁: μ > 35

α: 0.01

This is a one-tailed test so you have only one critical level (right tail):

Z_{1\alpha } = Z_{0.99} = 2.33

This means that if the value of the calculated statistic is equal or greater than 2.33 you will reject the null Hypothesis.

If the value is less than 2.33 you will support the null hypothesis.

The statistic is:

Z=<u> X[bar] - μ </u>= <u> 37.7 - 35 </u> = 2.93

       S/√n           9.2/10

The value 2.93 > 2.33, so you reject the null hypothesis. This means that the population mean of users that are connected at the same time is greater than 35.

<u><em>Note: </em></u><em>To make the decision using the interval calculated on a), the hypothesis should have been two-tailed and the confidence and significance levels complementary.</em>

I hope it helps!

7 0
3 years ago
5
Svetradugi [14.3K]

Answer:

The right answer is:

Option OB: f(1) = -9

Common difference: 7

Step-by-step explanation:

Given sequence is:

-9, -2, 5, 12,...

Here the first number is f(1)

Common Difference:

Common difference is the difference between consecutive terms of an arithmetic sequence. It is denoted by d.

In the given sequence,

f(1) = -9

f(2) = -2

f(3) = 5

d=f(2)-f(1) = -2-(-9) = -2+9 = 7\\d = f(3)-f(2) = 5-(-2) = 5+2 = 7

Hence,

The right answer is:

Option OB: f(1) = -9

Common difference: 7

7 0
3 years ago
Help me asap please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
zmey [24]

Answer:

D. should be the answer

3 0
3 years ago
Read 2 more answers
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