Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
x=5
Step-by-step explanation:
We can use the Triangle Angel Bisector Theorem
AB 2x-1
----------= --------------
AC 3x
9 2x-1
----------= --------------
15 3x
Using cross products
3x*9 = 15*(2x-1)
Distribute
27x = 30x-15
Subtract 30x from each side
27x-30x = 30x-30x-15
-3x = -15
Divide by -3
-3x/-3 =-15/-3
x =5
Answer: 3/20 of the class
Step-by-step explanation:
Add the amount of students that play soccer to amount of students that play volleyball
1/4 + 3/5 = 17/20
Subtract 17/20 (soccer and volley ball) from 20/20 or 1
20/20 - 17/20 = 3/20
