Let x+y=10 be equation (1)
and y=x-4 be equation (2)
from (2)
y=x-4...(3)
sub (3) into (1)
x+(x-4)=10
x+x-4=10
2x=12
x=6
sub (x) into (3)
y=6-4
y=2
Q+S-T
=7m+3n+n+5-(-m-3n+8)
=7m+3n+n+5+m+3n-8
=8m+7n-3
Answer:
2/12 if the spinner has 6 chooses. I think sorry if I'm wrong
Step-by-step explanation:
That is true. You basically add 4 because the chance of it landing on that side of the coin from being altered makes it more likely to be on that.