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2 years ago

What is the value of x when h(x) = −3?

Mathematics

1 answer:

CaHeK987 [17]2 years ago

8 0

Answer:

○ -1

Step-by-step explanation:

Looking closely at this piecewise function, when the line on the left-hand side intersects at -3 = y, x is -1.

i hope this work for you

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How do I do this I am a bit confused ?

Colt1911 [192]

When you multiply the same number with different exponents together, you add the exponents together.

3^2 + 3^x = 3^7

Adding the two together you have 3^(2 + x = 7)

Solve for x: 2 + x = 7

Subtract 2 from both sides:

x = 5

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2 years ago

Simplify the expression :)<br> pls help

Ad libitum [116K]

Answer:

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3 years ago

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Ronch [10]

Answer:

25.1cm

Step-by-step explanation:

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Put values in formula.

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2 years ago

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Luba_88 [7]

Answer:

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Step-by-step explanation:

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3 years ago

7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)

serg [7]

Answer:

$-\frac{x^2y^2}{2}$

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

$\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}$

Multiply the numerators :

$\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}$

Multiply the denominators :

$\frac{-18x^6y^4z^3}{36x^4y^2z^3}$

Apply the negative rule :

$-\frac{18x^6y^4z^3}{36x^4y^2z^3}$

Cancel the common factor which is 18 :

$-\frac{x^6y^4z^3}{2x^4y^2z^3}$

Apply the addition exponent rule :

$\frac{y^4z^3x^{6-4} }{2y^2z^3}$

Subtract :

$\frac{x^2y^4z^3 }{2y^2z^3}$

Apply the rule for y :

$\frac{x^2y^{4-2} z^3 }{2z^3}$

Subtract :

$\frac{x^2y^2z^3 }{2z^3}$

Cancel the common factor of z^3 :

$-\frac{x^2y^2}{2}$

5 0

3 years ago