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Elanso [62]
3 years ago
14

Pls help me with this answer

Mathematics
2 answers:
Misha Larkins [42]3 years ago
6 0

student 3 i thin srry if im wrong

olya-2409 [2.1K]3 years ago
5 0

Answer:

student 3

Step-by-step explanation:

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If the math club collected 17,604 points and gave away 36 shirts, how many points were collected if 82 shirts were given away?
luda_lava [24]
17,604 points/36 shirts=<span>489 points per shirt
</span>82 shirts*489 points=<span>40,098 points</span>
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2 years ago
A person who weighs 150 lbs. on Earth will weigh 24.9 lbs. on the Moon. What percent of the person's Earth weight will be their
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2 years ago
Can anyone help it would mean alot im struggling right now
Setler79 [48]

Answer:

what do you need? ^-^ I can help you

6 0
2 years ago
Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
____ [38]
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
y=2/3x-6/3


The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
-2=(-3/2)(6)+b       Combine like terms
-2=-9+b                 Add 9 in both sides to isolate b
7=b

The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


4 0
3 years ago
PLZ HELP ME WITH GEOMETRY
Aloiza [94]

B a counterclockwise rotation about the origin of 90°

under a counterclockwise rotation about the origin

a point ( x , y ) → (- y, x)

figure Q to figure Q'

( 4,2 ) → (- 2, 4 )

(7, 5 ) → (- 5, 7 )

(3, 7 ) → (- 7 , 3 )

(2, 4 ) → (- 4, 2 )

(5, 4 ) → (- 4, 5 )

the coordinates of the original points of the vertices of Q map to the corresponding points on the image Q'



7 0
3 years ago
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