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2 years ago

When 4(0.5x+2.5y-0.7x-1.3y+4) is simplified, what is the resulting expression?

Mathematics

2 answers:

padilas [110]2 years ago

8 0

Answer:

-0.8x + 4.8y + 16

Step-by-step explanation:

4(0.5x+2.5y-0.7x-1.3y+4) = 4( 0.5x - 0.7x + 2.5y - 1.3y + 4)

= 4( -0.2x + 1.2y + 4)

= 4*(-0.2x) + 4 *1.2y + 4*4

= -0.8x + 4.8y + 16

Bess [88]2 years ago

6 0

Answer:

-0.8x + 4.8y + 16

Step-by-step explanation:

hope this helps

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Which expression is equivalent to 7h^2-252k^2?

gulaghasi [49]

Answer:

Step-by-step explanation:

252 = 7 *36

36 = 6 *6 = 6²

a² -b² = (a + b)(a - b)

7h² - 252k² = 7(h² - 36k²)

= 7(h² - [6k]² )

= 7(h +6k)(h - 6k)

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3 years ago

Read 2 more answers

Sunny_sXe [5.5K]

Answer: A 13.4

Step-by-step

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2 years ago

zach's bird feeder holds 3/4 cup of birdseed. Zach is filling the bird feeder with a scoop that holds 3/8 of a cup. how many sco

mr Goodwill [35]

Answer:

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2 years ago

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6x(0,5x+3)+3x(1-x)-(1-10x)=7

Eddi Din [679]

Answer:

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Step-by-step explanation:

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3 years ago

Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)

Sedbober [7]

Answer: $\bold{y=-\dfrac{1}{3}x-1}$

Step-by-step explanation:

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\$

Next, find the midpoint of (4, 1) and (2, -5):

$Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)$

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

$y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\$

6 0

2 years ago