Answer:
Sample number 3
Step-by-step explanation:
From the given information:
Sample Service life(hours) Total Mean(X)
1 2 3 4
1 495 500 505 500 2000 500
2 525 515 505 515 2060 515
3 470 480 460 470 1880 470
Total = ![\text{addition \ of \ numbers \ of \ observations}](https://tex.z-dn.net/?f=%5Ctext%7Baddition%20%20%5C%20of%20%5C%20numbers%20%5C%20of%20%5C%20observations%7D)
Mean = ![\dfrac{\text{addition \ of \ numbers \ of \ observations}}{4}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7Baddition%20%20%5C%20of%20%5C%20numbers%20%5C%20of%20%5C%20observations%7D%7D%7B4%7D)
Thus;
![UCL = \mu+x = 500 + 20 = 520\\ \\ LCL= \mu -x = 500 -20 =480](https://tex.z-dn.net/?f=UCL%20%3D%20%5Cmu%2Bx%20%3D%20500%20%2B%2020%20%3D%20520%5C%5C%20%5C%5C%20%20LCL%3D%20%5Cmu%20-x%20%3D%20500%20-20%20%3D480)
To plot on an X_Bar chart, we have:
Sample Mean (X) UCL LCL
1 500 520 480
5 515 520 480
6 470 520 480
The x-Bar chart is shown in the image attached below. From the image, we realize that the average service life for sample number 3 occurs to be out of the statistical control.
![\large \mathfrak{Solution : }](https://tex.z-dn.net/?f=%5Clarge%20%5Cmathfrak%7BSolution%20%3A%20%7D)
The incorrect one is 35 × 10⁵
it can be written as :
I think the equation would be y=32000(1/2x). The y intercept would be, (16000 , 1) (8000 , 2) (4000 , 3).