EXPLANATION
Given the expression 2y(x-y) +12=5x , plugging in x=3 into the expression,
2y(3-y) + 12 = 5*3
6y -2y^2 + 12 = 15
Rearranging terms:
Now, we need to apply the quadratic equation:
Multiplying terms:
![y_{1,2}=\frac{-6\pm\sqrt[]{36-24}}{-4}](https://tex.z-dn.net/?f=y_%7B1%2C2%7D%3D%5Cfrac%7B-6%5Cpm%5Csqrt%5B%5D%7B36-24%7D%7D%7B-4%7D)
Subtracting numbers:
![y_{1,2}=\frac{-6\pm\sqrt[]{12}}{-4}](https://tex.z-dn.net/?f=y_%7B1%2C2%7D%3D%5Cfrac%7B-6%5Cpm%5Csqrt%5B%5D%7B12%7D%7D%7B-4%7D)
Simplifying:
No because if you multiply a three digit number by 0 you always get 0 and if you multiply 0.125 by 4 you get 0.5 or 0.450 times 2 is 0.9
Answer:
This product is 6.2(3c + 8)
Step-by-step explanation:
This product is 6.2(3c + 8). The factors are 6 and (3c + 8).
Answer:
The second option. y = 3x +3
Step-by-step explanation:
※ x = -4
y = 3(-4) + 3
= -12 + 3
= -9
※ x = 3
y = 3(3) +3
= 9 + 3
= 12
Answer:
I think it b
Step-by-step explanation:
I had to ADD 4.2+3
