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Kobotan [32]
3 years ago
14

What is log2^45 to four decimal places? a.5.4919 b.3.8067 c.1.3522 d.0.1821

Mathematics
1 answer:
ehidna [41]3 years ago
4 0
I’m petty sure it’s C
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HALPPPPP PLZZZ I'll give Brainliest for the first answer CORRECT
ddd [48]

Answer:

Since it is area, it is most defined as base times height, so the larger rectangle would be 9x14 which is 126 and the smaller rectangle is 6x8 which is 48, and since they are together in one shape, you can add both areas which would give you an answer of 174

Step-by-step explanation:

7 0
3 years ago
The probability that Barry Bonds hits a home run on any given at-bat is 0.16, and each at-bat is independent.
serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that p = 0.16

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136


0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

E = \frac{n}{p}

In this question, n = 1, p = 0.16. So

E = \frac{1}{0.16} = 6.25

The expected number of at-bats until the next home run is 6.25.

6 0
2 years ago
3.6399; thousandths round it ​
shepuryov [24]

Answer:

3.6399 = 3.640

Step-by-step explanation:

3.6399\\1\:2\:3

Rounding to nearest thousandth means rounding to 3 decimal place

(0 to 4) =round down

(5 to 9)= round up

3 0
3 years ago
Use each of the digits 2, 3, 7, and 8. Make it two different multiplication problems so that each product is larger than 5000. U
SVEN [57.7K]
83 x 72 = 5,976. 82 x 73 = 5,986. The way to do this is to take the two biggest numbers and use them in the tens place. Then take the other numbers and put them in the ones space. Then switch the ones slot numbers around to get two different numbers over 5000.
6 0
3 years ago
X/-5=-20<br><br> A -100 or 100<br> B -4 or 4<br> C 100<br> D no solution
alexgriva [62]

Move the negative sign to the left

-x/5 = -20

Multiply both sides by 5

-x = -20 × 5

Simplify 20 × 5 to 100

-x = -100

Multiply both sides by -1

<em>x = 100</em>

<u>C. 100</u>

4 0
3 years ago
Read 2 more answers
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