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agasfer [191]
2 years ago
9

Rosie and Dan share some sweets. Dan gets 1/4 of the sweets. Write down the ratio of the number of sweets Rosie gets to the numb

er of sweets Dan gets
Mathematics
2 answers:
Fiesta28 [93]2 years ago
4 0
3:1 because she is left with 3/4 of the sweets which is 3 times what Dan got. If you need to put it in fraction form it’s 3/1
ziro4ka [17]2 years ago
3 0

Answer: 3:1

Step-by-step explanation:

Given:

Rosie and dan share some sweets.

Dan gets ¼ of sweets

To find:

Write down the ratio of the number of sweets Rosie to the number of sweets Dan gets

the ratio of the number of sweets Rosie gets to the number of sweets Dan gets is → 3 : 1.

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Vinvika [58]

Answer:

t=21

Step-by-step explanation:

5 0
2 years ago
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Help<br> Please<br> I<br> Don’t<br> Understand
Nat2105 [25]

Answer: -4x+5>-5=x>2.5

-25>-5(x+2.5)=x<2.5

Step-by-step explanation:

-4x+5>-5 -25>-5(x+2.5)

-5 -5 -25>-5x-12.5

-4x>-10 +12.5 +12.5

/-4 /-4 -12.5>-5x

x>2.5 /-5 /-5

2.5>x

x<2.5

3 0
3 years ago
5 yd<br> 3 yd<br> 4.8 yd<br> 28 yd<br> 8 yd
kompoz [17]

Answer:

i am converting to meters

Step-by-step explanation:

5 yd =4.572 meters

3yd=2.7432 meters

4.8yd=2.7432 meters

28yd=25.6032 meters

8yd=7.3152 meters

5 0
3 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?
trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0
2 years ago
Read 2 more answers
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