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hoa [83]
3 years ago
13

Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n

ewspapers did Ray deliver in the second hour?
Mathematics
1 answer:
Temka [501]3 years ago
8 0

Answer:

\frac{1}{2}

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= \frac{3}{8} of x

Total number of newspapers delivered in first hour= \frac{3}{8}x

Number of newspapers left= x-\frac{3x}{8}

Number of newspapers left=\frac{8x-3x}{8}

Number of newspapers left=\frac{5x}{8}

Number of newspapers delivered in second hour=4/5 of\frac{5x}{8}

Number of newspapers delivered in second hour=\frac{x}{2}

Fraction of newspapers delivered in second hour is=\frac{1}{2}

Hence, the correct answer is \frac{1}{2}

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PLZ HELP ME PLZ I NEED THE HELP
Dmitrij [34]

Answer:

<M = <S

Step-by-step explanation:

If ΔMNO ≅ Δ SQR then

<M = <S


5 0
3 years ago
The sum of Ted's and Leon's ages is
olganol [36]

Answer:

Ted is 6 years old

Leon is 7 years old

Andrew is 8 years old

Step-by-step explanation:

Ted+Leon=13 ⇒T+L=13 ⇒L=13-T

Leon+Andrew=15 ⇒L+A=15 ⇒A=15-L ⇒A=15-(13-T) because Leon =13-Ted

A=2+T

Ted+Andrew=14

T+A=14  ( substitute Andrew age from A=2+T)

T+2+T=14

2T=12

<h2>T=12/2=6 (Ted is 6 years old)</h2><h2>A=2+T=2+6=8 ( Andrew is 8 years old)</h2><h2>Leon=13-T=13-6=7 ( Leons is seven years old)</h2>

check: Ted+Leon=13 ⇒ 6+7=13

Leon + Andrew=15 ⇒7+8=15

Andrew+Ted=14 ⇒ 6+8=14

7 0
3 years ago
A puppy was born on April 1. The table gives the puppy's weights on three different
Masja [62]

Answer:

it is the middle one

Step-by-step explanation:

i did it

6 0
3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
Sliva [168]
\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}
\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}
\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}
\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}
\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
5 0
3 years ago
Zoe is working two summer jobs, making $7 per hour babysitting and making $15 per
Rasek [7]

Answer:

7, 8, 9, 10

Step-by-step explanation:

If Zoe worked 4 hours of babysitting at $7 per hour, she earned $28. Therefore, she must earn another $102 to earn at least $130. At $15 per hour, she must work a minimum of 7 hours clearing tables to make at least $102. This is fine since she can work another 10 hours before reaching her maximum of 14 total hours. Therefore, all possible values for the number of whole hours clearing tables that she must work to meet her requirements are 7, 8, 9, 10.

6 0
3 years ago
Read 2 more answers
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