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3 years ago

A(q-8)=23solve for qhelp appreciated!

Mathematics

2 answers:

OLga [1]3 years ago

8 0

(I’m not sure if the A is part of the question or if A is what question you’re answering but I’ll work o for both)

A(q - 8) = 23

Multiply everything inside the brackets by A:

aq- 8a = 23

Divide both sides by a to isolate q - 8a:

q - 8a = 23 / a

Add 8a to both sides to isolate q:

q = 23 + 8a² / a

Without the A:

q - 8 = 23

Add 8 to both sides to isolate q:

q = 31

Sorry if I misunderstood but I hope I helped you, have a great day!!

SIZIF [17.4K]3 years ago

6 0

Answer:

q= (23+8a)/a

Step-by-step explanation:

a(q-8)=23

or, aq-8a = 23

or, aq = 23+8a

or, q = (23+8a)/a

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The shapes below are mathematically similar.

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Triangle small ABC

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I hope I helped you^_^

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4 years ago

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3 years ago

Read 2 more answers

HELP DUE IN 10 MINS!

Scilla [17]

Answer:

$\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi$

Step-by-step explanation:

Area of a circle with radius $r$ : $r^2\pi$

Circumference of a sector with radius $r$ : $2r\pi$

Area of sector with angle $\theta$ : $r^2\pi\cdot \frac{\theta}{360}$ .

Arc length of sector with angle $\theta$ : $2r\pi\cdot \frac{\theta}{360}$

Using these equations, we get the following information:

Area of circle: $27^2\pi=729\pi$

Circumference of a circle: $2\cdot 27\cdot \pi=54\pi$

Area of sector: $27^2\pi\cdot \frac{80}{360}=162\pi$

Arc length of sector: $2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi$

3 0

3 years ago

A(q-8)=23solve for qhelp appreciated! ​

A(q-8)=23solve for qhelp appreciated!