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Zina [86]
3 years ago
13

Which measure of central tendency is least appropriate for describing the given data set?. 6, 6, 6, 7, 8, 8, 29. . a. mode. b. m

edian. c. mean. . i think mode, is it right??
Mathematics
1 answer:
maksim [4K]3 years ago
4 0
Mode is which number appears the most. Mean is adding up all the numbers and dividing by the amount of numbers. Median is the middle number of the ordered numbers from least to greatest. Look at the set. they are in order so median is off. Numbers appear more than once so mode is off. However, mean is not there. We don't have an average. (adding up the numbers and dividing by amount.) So the answer should be mean. 

good luck!
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HELPPP!! Calculate the side lengths a and b to two decimal places. (there is a picture included)
lara31 [8.8K]

Answer:

Option (D)

Step-by-step explanation:

In the given triangle ABC,

Sum of all interior angles = 180°

m∠A + m∠B + m∠C = 180°

72° + 85° + m∠C = 180°

m∠C = 180 - 157

m∠C = 23°

By applying Sine rule in the triangle,

\frac{\text{SinA}}{a}=\frac{\text{SinB}}{b}=\frac{\text{SinC}}{c}

\frac{\text{Sin72}}{a}=\frac{\text{Sin85}}{b}=\frac{\text{Sin23}}{6.2}

\frac{\text{Sin72}}{a}=\frac{\text{Sin85}}{b}=0.06302

\frac{\text{Sin72}}{a}=0.06302

a = \frac{\text{Sin72}}{0.06302} = 15.09

\frac{\text{Sin85}}{b}=0.06302

b = \frac{\text{Sin85}}{0.06302}

b = 15.81

Therefore, option (D) will be the answer.

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2 years ago
Use the following terms to describe the challenging environment of west and central Africa : Deforestation, desertification, mal
Neporo4naja [7]
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2 years ago
Which is the net for this rectangular prism?
dybincka [34]

Answer:

On the left the one down below

Step-by-step explanation: I check it to make sure it was right

3 0
2 years ago
In a random sample of 60 shoppers 12 said that they only buy products that are on sale. If there are 3000 shoppers at the mall t
dimulka [17.4K]

Answer:

Number of shopper buy from sale [3,000shopper] = 600 (Approx.)

Step-by-step explanation:

Given:

Number of shopper in mall = 60

Number of shopper buy from sale = 12

Find:

Number of shopper buy from sale if total number number of shopper are 3,000

Computation:

Number of shopper buy from sale [3,000shopper] = 3000[Number of shopper buy from sale/Number of shopper in mall]

Number of shopper buy from sale [3,000shopper] = 3000[12 / 60]

Number of shopper buy from sale [3,000shopper] = 3000[1/5]

Number of shopper buy from sale [3,000shopper] = 600 (Approx.)

4 0
3 years ago
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les
kaheart [24]

Answer:

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

\hat p=0.52 estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

\alpha=0.05 represent the significance level (no given, but is assumed)    

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

5 0
2 years ago
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