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BigorU [14]
3 years ago
5

Help help help help ill like five y’all brian list or something just pls help

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0
Hi can someone help me for correcting my text
lubasha [3.4K]3 years ago
5 0

Answer: 0.086x

Step-by-step explanation:

Since the trend line starts at the origin, there is no y-intercept. To calculate the slope, divide the change in y over change in x. Since one of our points is the origin, we can just divide the y value by the x value, or 1.38 by 16, to get 0.08625. Rounded to the nearest thousandth, we get a slope of 0.086.

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At what point does she lose contact with the snowball and fly off at a tangent? That is
postnew [5]

Answer:

α ≥ 48.2°

Step-by-step explanation:

The complete question is given as follows:

" A skier starts at the top of a very large frictionless snowball, with a very small initial speed, and skis straight  down the side. At what point does she lose contact with the snowball and fly off at a tangent? That is, at the  instant she loses contact with the snowball, what angle α does a radial line from the center of the snowball to  the skier make with the vertical?"

- The figure is also attached.

Solution:

- The skier has a mass (m) and the snowball’s radius (r).

- Choose the center of the snowball to be the zero of gravitational  potential. - We can look at the velocity (v) as a function of the angle (α) and find the specific α at which the skier lifts off and  departs from the snowball.

- If we ignore snow-­ski friction along with air resistance, then the one work producing force in this problem, gravity,  is conservative. Therefore the skier’s total mechanical energy at any angle α is the same as her total mechanical  energy at the top of the snowball.

- Hence, From conservation of energy we have:

                       KE (α) + PE(α) = KE(α = 0) + PE(α = 0)

                       0.2*m*v(α)^2 + m*g*r*cos(α) = 0.5*m*[ v(α = 0)]^2 + m*g*r

                       0.2*m*v(α)^2 + m*g*r*cos(α) ≈ m*g*r

                        m*v(α)^2 / r = 2*m*g( 1 - cos(α) )

- The centripetal force (due to gravity) will be mgcosα, so the skier will remain on the snowball as long as gravity  can hold her to that path, i.e. as long as:

                         m*g*cos(α) ≥ 2*m*g( 1 - cos(α) )

- Any radial gravitational force beyond what is necessary for the circular motion will be balanced by the normal  force—or else the skier will sink into the snowball.

- The expression for α_lift becomes:

                            3*cos(α) ≥ 2

                            α ≥ arc cos ( 2/3) ≥ 48.2°

4 0
3 years ago
The formula for the surface area of a rectangular prism with a square base is SA=2s2+4shSA=2s2+4sh. What is the surface area of
Ivanshal [37]
This is the concept of algebra, given that the formula for the surface area of the prism is modeled by the expression SA=2s²+4sh , the surface area of the prism when s=3 and h=5 will be found by substituting the values in our expression as follows;
SA=2(3)²+4×3×5
SA=2(9)+60
SA=18+60
SA=78 sq. units
The answer is 78 sq. units

4 0
2 years ago
Read 2 more answers
Can someone please solve and explain these questions??? ​With work please.
ankoles [38]
Y=1 because on each equation it needs 1 for it to be the answer
8 0
2 years ago
Simplify the expression.<br> -5(7m + 9) =
OlgaM077 [116]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

-5(7m + 9)  Equation/Question

Step 2

-5(7m + 9)  Simplify

(-5)(7m+9)

Step 3

(-5)(7m+9)  Multiply

-35m-45

Answer

-35m-45

Hope this helps

6 0
3 years ago
Read 2 more answers
What is the slope of this line? y=4x+6
ruslelena [56]

Answer:

The slope is 4

Step-by-step explanation:

So the formula is y=mx+b. M is the slope and b would be your y intercept. So the slope is 4. (I just did this in class)

7 0
3 years ago
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