3 years ago

Given that segments AE = 4 in, DE = 12 in, and EF = 8 in.

1 answer:

8 0

We know that
When two chords intersect each other inside a circle, the products of their segments are equal (Intersecting Chord Theorem)
so
AE*EB=DE*EF-----> EB=DE*EF/AE
AE=4 in
DE=12 in
EF=8 in
EB=?
EB=DE*EF/AE
EB=12*8/4-----> EB=24 in

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